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3 years ago

PLEASE HELP!

Mathematics

2 answers:

Blababa [14]3 years ago

8 0

The lateral area is the area of the three triangular sides in white. Do not include the area of the triangular base in grey.

Looking at the net to the right, you see the base and height of each white triangle.

Back side: base = 6 in.; height = 5.2 in.
Right side: base = 3 in.; height = 5.8 in.
Left side: base = 6 in.; height = 5.2 in.

Area of triangle = bh/2

A(back) = (6 in.)(5.2 in.)/2 = 15.6 in.^2
A(right) = (3 in.)(5.8 in.)/2 = 8.7 in.^2
A(left) = (6 in.)(5.2 in.)/2 = 15.6 in.^2

Lateral area = 15.6 in.^2 + 8.7 in.^2 + 15.6 in.^2 =

Lateral area = 39.9 in.^2

slava [35]3 years ago

5 0

If the lateral surface is just the three side triangles: 39.9 in^2

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$\large\underline{\sf{Solution-}}$

Given that,

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