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zloy xaker [14]
3 years ago
9

Please help I don’t understand

Mathematics
2 answers:
natta225 [31]3 years ago
8 0

Answer:

f= 11

Step-by-step explanation:

Plug in 7, for the variable t. It will equal 14 because 2 times 7 is 14. Subtract 3 from 14, and the answer is 11.

Here is the work shown.

f= 2t - 3, t= 7

f= 2(7) - 3

f= 14 - 3

f= 11

I hope this helps. :)

maria [59]3 years ago
3 0

Answer:

f= 11

Explanation:

f= 2t-3 when t= 7 (just plug in 7 for the variable t!)

f= 2(7)-3

f= 14-3

f= 11

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Use the figure to the right to find the value of PT. T is the midpoint of PQ.
Ghella [55]

Answer:

<em>PT=30 units</em>

Step-by-step explanation:

Given that:

Line PQ which has a mid point at T.

PT = 3x + 9 and

TQ = 5x -5

To find:

PT = ? in simplified terms.

Solution:

First of all, let us recall that mid point on a line segment is a point that divides the line in two equal parts.

In other words:

If a point B is the mid point of line segment AC, then AB = BC.

Here, the point T is the midpoint of PQ.

i.e. PT = TQ

3x+9=5x-5\\\Rightarrow 3x-5x=-5-9\\\Rightarrow -2x=-14\\\Rightarrow x=7

Putting value of x in PT above:

PT = 3x+9 = 3 \times 7 +9 \\\Rightarrow \bold{PT=30\ units}

7 0
3 years ago
10. (a) Consider the following matrices: A = ( 2 ) B = (3) and C = (-3) w = Find the det(A). [1] (ii) Is the matrix A singular?
Viefleur [7K]

i) We have to find the determinant of A.

We can do this as:

\det(A)=|\begin{bmatrix}{3} & {6} \\ {1} & {-2}\end{bmatrix}|=3*(-2)-6*1=-6-6=-12

ii) We have to find if the matrix A is singular.

Singular matrix have determinant equal to 0.

This is not the case for A, as its determinant is -12. Then, A is not a singular matrix.

iii) We have to find the values of x and y so that AB = C.

We have to write the matrix multiplication and we will obtain a system of linear equations:

We can now solve the system of equations by adding 3 times the second equation to the first equation:

\begin{gathered} 3(x-2y)+(3x+6y)=3(-3)+(-3) \\ 3x-6y+3x+6y=-9-3 \\ 6x+0y=-12 \\ x=\frac{-12}{6} \\ x=-2 \end{gathered}

We can now use the second equation to find the value of y:

\begin{gathered} x-2y=-3 \\ x+3=2y \\ y=\frac{x+3}{2} \\ y=\frac{-2+3}{2} \\ y=\frac{1}{2} \end{gathered}

The values are x = -2 and y = 1/2.

iv) When we want to multiply two matrices, the required condition is that the number of columns of the matrix on the left is equal the number of rows of the matrix on the right.

In the case of A(2x2) and B(2x1), when we do A*B this condition is satisfied.

But when we try to multiply BA, the number of columns of B is not equal to the number of rows of A, so the matrix mulitplication is not possible.

Answer:

i) det(A) = -12

ii) A is not singular because singular matrices have determinant equal to zero.

iii) x = -2 and y = 1/2.

iv) Is not possible because the number of columns of the first matrix has to be equal to the number of rows of the second matrix.

6 0
1 year ago
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Maslowich

Answer:

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7 0
3 years ago
Read 2 more answers
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navik [9.2K]

Answer:

4x+1

Step-by-step explanation:

The area is 12x2 + 3x in

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12x2 + 3x=3x*B

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12x2+3x divide by 3x=B

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The express for the width is 4x+1

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