<span>Hello!
We have the following data:
W (molality) = ? (in Molal)
m1 (mass of the solute) = 14.7 g
m2 (mass of the solvent) =? (in Kg)
d (</span><span>solvent density) = 1,00 g/mL
</span>V (volume of the solvent) = 150 mL
<span>The mass of the solvent will be found by the following formula
</span>
![d = \dfrac{m_2}{V}](https://tex.z-dn.net/?f=d%20%3D%20%20%5Cdfrac%7Bm_2%7D%7BV%7D%20)
![1 = \dfrac{m_2}{150}](https://tex.z-dn.net/?f=1%20%3D%20%5Cdfrac%7Bm_2%7D%7B150%7D%20%20)
![m_2 = 1*150](https://tex.z-dn.net/?f=m_2%20%3D%201%2A150%20)
<span>
</span>
![m_2 = 150\:g\to \boxed{m_2 = 0,15\:Kg}](https://tex.z-dn.net/?f=m_2%20%3D%20150%5C%3Ag%5Cto%20%5Cboxed%7Bm_2%20%3D%200%2C15%5C%3AKg%7D)
<span>
M1 (Molar mass of solute - </span>C6H12O6) = ?
C = 6*12 = 72 u
H = 12*81 = 12 u
O = 6*16 = 96 u
------------------------
M1 (Molar mass of solute - C6H12O6) = 72+12+96 = 180 g/mol
<span>Now, let's find Molality, applying the above data to the formula, let's see:
</span>
![\omega = \dfrac{m_1}{M_1*m_2}](https://tex.z-dn.net/?f=%5Comega%20%3D%20%20%5Cdfrac%7Bm_1%7D%7BM_1%2Am_2%7D%20)
![\omega = \dfrac{14,7}{180*0,15}](https://tex.z-dn.net/?f=%5Comega%20%3D%20%5Cdfrac%7B14%2C7%7D%7B180%2A0%2C15%7D)
![\omega = \dfrac{14,7}{27}](https://tex.z-dn.net/?f=%5Comega%20%3D%20%5Cdfrac%7B14%2C7%7D%7B27%7D)
I hope this helps. =)