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irga5000 [103]
3 years ago
13

Compare natural selection to evolution. Be sure to justify your response in two or more complete sentences.

Chemistry
1 answer:
WINSTONCH [101]3 years ago
7 0
Natural selection is the process in which a weaker, or less advantaged animal loses something to a stronger, more advantaged animal. For example, a frog with a broken leg probably will not get to mate while a healthy  frog will. Evolution is the process of an animal gradually changing over the generations biologically. An example of this is the theory that humans slowly evolved from monkeys, gradually becoming more and more human like.
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Which of the following is a property of acids
m_a_m_a [10]

Answer:

They are sour. =)

Explanation:

3 0
3 years ago
Read 2 more answers
Sodium phosphate and calcium chloride react to form sodium chloride and calcium phosphate. If you have 379.4 grams of calcium ch
GalinKa [24]

Answer:- A. 353.5 g

Solution:- The balanced equation is:

2Na_3PO_4(aq)+3CaCl_2(aq)\rightarrow 6NaCl(aq)+Ca_3(PO_4)_2(s)

From this equation, there is 3:1 mol ratio between calcium chloride and calcium phosphate.

Grams of calcium chloride are converted to moles and these moles are multiplied by the mol ratio to get the moles of calcium phosphate. Finally the moles are multiplied by molar mass to get the grams of calcium phosphate.

Molar mass of CaCl_2 = 40.078+2(35.45) = 110.978 g per mol

Molar mass of Ca_3(PO_4)_2 = 3(40.078)+2(30.974)+8(16.00)

= 120.234+61.948+128.00 = 310.182 g per mol

let's make the set up using dimensional analysis.

379.4gCaCl_2(\frac{1molCaCl_2}{110.978gCaCl_2})(\frac{1molCa_3(PO_4)_2}{3molCaCl_2})(\frac{310.182gCa_3(PO_4)_2}{1molCa_3(PO_4)_2})

= 353.5gCa_3(PO_4)_2

Hence, 353.5 g of calcium phosphate will form and so the correct option is A.

8 0
3 years ago
A 27.5 −g aluminum block is warmed to 65.9 ∘C and plunged into an insulated beaker containing 55.5 g water initially at 22.1 ∘C.
Wittaler [7]

Answer:

The final temperature of aluminium ≈ 26.32 °C

Explanation:

<u>Step 1:</u> explain the problem

A 27.5 −g aluminum block is warmed to 65.9 ∘C and plunged into an insulated beaker containing 55.5 g water initially at 22.1 ∘C.

<u>Step 2:</u> Data given

We will use the formule : Q = mcΔT

with Q = heat transfer ( J)

with m = mass of the substance (g)

with c = specific heat ( J/g °C)

with ΔT = change in temperature ( in °C or K)

mass of aluminium = 27.5g

mass of water = 55.5g

specific heat of aluminium = 0.900J/g °C

specific heat of water = 4.186 J/g °C

initial temperature of aluminium T1= 65.9 °C

initial temperature of water T1 =  22.1 °C

final temperature of water and aluminium = TO BE DETERMINED

<u>Step 3:</u> Calculate the initial temperature

To find the final temperature, we have to use the  following formule:

-(Mass of aluminium) * (caluminium)*(ΔT)) = (Mass of water) *(cwater)*(ΔT)

-27.5g (0.900)(T2 - 65.9) = 55.5g (4.184j/g °C) (T2- 22.1)

-24.75*(T2-65.9) = 232.212 *(T2-22.1)

-24.75T2 + 1631.025 = 232.212T2 -5131,8852

-256.962 T2 = -6762.9102

T2 = 26.32 °C

The final temperature of aluminium ≈ 26.32 °C

6 0
3 years ago
Coffee is<br><br> homogeneous.<br><br> heterogeneous.
Basile [38]
The answer is homogeneous
3 0
3 years ago
67g of K2O is how many moles
taurus [48]
Follow the formula.. there’s not enough in this question for me to solve
7 0
3 years ago
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