Answer:
Qsp > Ksp, BaCO3 will precipitate
Explanation:
The equation of the reaction is;
Na2CO3 + BaBr2 -------> 2NaBr + BaCO3
Since BaCO3 may form a precipitate we can determine the Qsp of the system.
Number of moles of Na2CO3 = 0.96g/106 g/mol = 9.1 * 10^-3 moles
concentration of NaCO3 = number of moles/volume of solution = 9.1 * 10^-3 moles/10 L = 9.1 * 10^-4 M
Number of moles of BaBr2 = 0.20g/297 g/mol = 6.7 * 10^-4 moles
concentration of BaBr2 = 6.7 * 10^-4 moles/10 L = 6.7 * 10^-5 M
Hence;
[Ba^2+] = 6.7 * 10^-5 M
[CO3^2-] = 9.1 * 10^-4 M
Qsp = [6.7 * 10^-5] [9.1 * 10^-4]
Qsp = 6.1 * 10^-8
But, Ksp for BaCO3 is 5.1*10^-9.
Since Qsp > Ksp, BaCO3 will precipitate
The answer to the question is Dna
Answer:
1.5 moles of CO₂ are produced
Explanation:
Based on the chemical equation:
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O<em> -The reaction of the question is wrong-</em>
5 moles of oxygen reacts per mole of propane, C₃H₈, to produce 3 moles of CO₂ and 4 moles of water.
If 2.5 moles of oxygen react and, 5 moles of oxygen produce 3 moles of CO₂, moles of CO₂ produced are:
2.5 moles O₂ * (3 moles CO₂ / 5 moles O₂) =
<h3>1.5 moles of CO₂ are produced</h3>