Distilled water is touched by man so it would probably be close to 300 degrees farenheit.......maybe.
When sodium carbonate and magnesium nitrate solutions are combined, a precipitate is created as a result of a double-displacement process. As you balance the chemical equation, make predictions about the reaction's byproducts.
<h3>What occurs when magnesium sulfate and sodium carbonate are combined?</h3>
A solid may form when the solutions of two soluble salts are combined. Salts that are insoluble are created during precipitation processes. When magnesium sulfate and sodium carbonate are combined, magnesium carbonate, an insoluble salt, results.
<h3>What happens when hydrochloric acid and sodium carbonate interact?</h3>
What takes place when sodium carbonate and hydrochloric acid interact? When sodium carbonate is added to hydrochloric acid, a double displacement reaction takes place, resulting in the formation of sodium chloride, water, and carbon dioxide. The sodium carbonate and the two moles of HCl combine to generate carbonic acid.
to know more about magnesium and sodium carbonate here:
brainly.com/question/28901831
#SPJ4
Answer:
Percent relative error = 0.191%
Explanation:
Relative error is a measure of accuracy (How closeness is the measure to the accepted value) for a determined data. The formula is:
Percent relative error = |Experimental - Accepted| / Accepted * 100
<em>Where experimental is the average of the data:</em>
(40.220g/mol + 40.654g/mol + 40.314g/mol + 40.165g/mol + 40.554g/mol) / 5 =
40.381g/mol
Replacing using accepted value = 40.304g/mol:
|40.381g/mol - 40.304g/mol| / 40.304g/mol * 100
<h3>Percent relative error = 0.191%</h3>
Answer:
H+ + OH− --> H2O
Explanation:
Hydrochloric acid is represented by the chemical formular; HCl. This is an ionic substance so in water it breaks apart into hydrohrn ions; H+ and chloride ions; Cl−. It is a strong acid, hence it completely dissociates.
Potassium Hydroxide is also an ionic substance it also breaks apart in water into potassium ions; K+ and hydroxide ions; OH−. It is a strong base, hence it completely dissociates.
The complete ionic equation for the reaction is given as;
H+ + Cl− + K+ + OH− --> K+ + Cl− + H2O
The Hydrogen ion and the Hydroxide ions combine to form water.
The net ionic equation is given as;
H+ + OH− --> H2O
Cl- and K+ ions were cancelled out because they do not undergo any changes therefore are not part of the net ionic equation. They are referred to as spectator ions.
Interesting problem. Thanks for posting.
C2H2 + (3/2)02 ====> H2O + 2CO2
CH4 + 2O2 =====> 2H2O + CO2
The molar mass of C2H2 = 2*12 + 2*1 = 26
The molar mass of CH4 = 1*12 + 4*1 = 16
The number of moles of C2H2 = x
The number of moles of CH4 = y
26x + 16y = 230.9 grams
For water we get (from the C2H2). Water has a molar mass of 2*1 + 16 = 18
x*18 See the balanced equation to see what it is the same number of moles as C2H2
From the methane we get
y*18
2*y* 18. Again see the balanced equation to see where that 2 came from.
18x + 36y is the total amount of water.
Now for the CO2. CO2 has a molar mass of 12 + 2*16 = 44
From C2H2 we get 2*44*x = 88x grams of CO2
From CH4 we get 1*y*44 grams of CO2
88x + 44y for CO2
Now we total to get the grand total of water and CO2
18x + 44y + 88x + 44y = 972.7 grams total.
106x + 88y = 972.7
Two equations, two unknowns, we should be able to solve this problem
26x + 16y = 230.9
106x + 88y = 972.7
I'm not going to go through the math unless you request me to do so.
x = 8.03 moles
y = 1.38 moles
The initial amount of C2H2 was 8.03 * 26 = 208.78
The initial amount of CH4 was 16*1.38 = 22.08
The total (as a check is 230.86 which is pretty close to the given amount.
So Methane's mass in the initial givens was 22.08 grams.
