Nitrogen has 5 valence electrons.
Answer:
Q 3 = lightning
Q 4 = False because there is also a fourth state of matter which is called plasma.
Q 5 = most of the matter in universe is made up of plasma.
Explanation:
Plasma:
" The ionized gaseous mixture consist of atoms, ions and electrons is called plasma"
The plasma was first time identified by William Crookes in 1879. More than 99% universe matter is consist of plasma.
It is the fourth state of matter, the other three are solid, gas and liquid. The most of matter in the universe is plasma. When heat is supplied to the atoms, they gain energy the electrons in atom thus escape from the atom by gaining the energy and create the positive charge. Thus ions are formed. When heat is constantly supplied, the ionization process continue to take place and produce large number of positive charges, free electrons but some atoms not get ionized and remain neutral. Thus a cloud of free electrons , positive charge and neutral atoms is formed which is called plasma.
Examples:
The shining stars, lightning bolts, fluorescent light, flames, electrical current which passes through neon gas are some examples of plasma.
Answer:C. distillation
Explanation:
Compounds having different boiling points when mixed can be separated by Fractional distillation.
Now when there is a mixture of water and alcohol, Upon heat, we would see that the alcohol will boil at a lower temperature than water for eg, ethanol will boil at 78.5 degrees Celsius, vaporizes and distills into the fractionating columns leaving the water which we know boils at 100 degrees Celsius.
See related link here :brainly.com/question/13113349
Reduction takes place in cathode while oxidation takes place at the anode.
Given that the reaction 3MnO4- +24H + +5Fe→3Mn+2+5Fe+3+12H2O
Now that oxidation is termed as an increase in oxidation number or loss of electrons while reduction is a decrease in oxidation number and gain of electrons,
∴oxidation will be
Fe→Fe +3+3e-
reduction will
MnO4- +8H+ →Mn+2+4H2O
If oxidation takes place at anode then Anode: an oxidation reaction
Fe→Fe+3+3e- . Then the answer is
Fe(s)→Fe+3(aq)+3e-
