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antoniya [11.8K]
2 years ago
7

Prove that \displaystyle \frac{\cos \theta}{1 + \sin \theta} = \frac{1 - \sin \theta}{\cos \theta}

Mathematics
1 answer:
Bogdan [553]2 years ago
7 0

Answer:

sin^2(θ)+cos^2(θ)=1

Step-by-step explanation:

We know that the statement above is true because of the Pythagorean identity theorem, which states the aforementioned equation. If you solve the equation for 1 you get the same equation.

To do this first multiply both sides by cos(θ), this gives you (cos^2θ)/1+sinθ = 1-sinθ

Then, multiply both sides by sinθ. This equals cos^θ=1-sin^2θ.

Finally, add sin^2θ to both sides. This equals the final answer of cos^2θ+sin^2θ=1. Which is true.

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2 years ago
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2 years ago
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undefined

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5 0
2 years ago
Read 2 more answers
In parallelogram MNOP , PK=5x and KN=x2−14 .
ololo11 [35]
<span>PK=5x and KN=x2−14 
</span>PK = KN
so
5x = x^2 - 14
x^2 - 5x - 14 = 0
(x -7)(x+2) = 0
x+2=0,x = -2
x-7=0;x = 7
so answer for x is 7
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answer
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7 0
3 years ago
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