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Alex_Xolod [135]
2 years ago
9

Do anyone know science??

Chemistry
2 answers:
Romashka [77]2 years ago
5 0

Yes I know science but why are you asking a question like this?

Vsevolod [243]2 years ago
3 0

Answer:

I do not understand.

Explanation:

What do you mean by that?

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A hypothesis is made before the experiment is conducted. <br> True or fasle
Viefleur [7K]

It should be at beginning. A hypothesis is called an educated guess of what might happen in the experiment.

Please brainliest

5 0
3 years ago
What is ΔE in kJ for a system that receives 1.79 kJ of heat from surroundings and has 4.51 kcal of work done on it at the same t
kenny6666 [7]

Answer: 20.7 kJ

Explanation:

According to first law of thermodynamics:

\Delta E=q+w

\Delta E=Change in internal energy

q = heat absorbed or released

w = work done or by the system

w = work done on the system=-P\Delta V  {Work is done on the system is positive as the final volume is lesser than initial volume}

w = 4.51 kcal = 4.51\times 4.184kJ=18.9kJ    (1kcal = 4.184kJ)

q = +1.79 kJ   {Heat absorbed by the system is positive}

\Delta E=+1.79+(18.9)=20.7kJ

Thus \Delta E for a system that receives 1.79 kJ of heat from surroundings and has 4.51 kcal of work done on it at the same time is 20.7 kJ

4 0
3 years ago
What is the independent variable?<br> (For science)
DiKsa [7]

Answer:

The independent variable is what you change in the experiment.

Explanation:

The independent determines the dependent variable.

6 0
3 years ago
How can you distinguish between a solution, colloid, and suspension?
RSB [31]

Answer:

solution is clear solution while colloidal is between the solution and suspension. And in suspension particles are suspended.

Explanation:

In solution light can be passed without any scattering of light from solute particles while suspension is cloudy and having larger particle size than colloids, if suspension stands for a while particles will settle down easily.

In colloids light  will scattered and dispersed by reflecting with large particles.

3 0
3 years ago
What volume, in milliliters, of a 0.997 M KOH solution is needed to neutralize 30.0 mL of 0.0400 M HCl?
deff fn [24]

Answer:

1.2 mL

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated:

HCl + KOH —> KCl + H₂O

From the balanced equation,

Mole ratio of the acid, HCl (nₐ) = 1

Mole ratio of base, KOH (n₆) = 1

Finally, we shall determine the volume of the base, KOH needed to neutralize the acid, HCl as follow:

Molarity of base, KOH (M₆) = 0.997 M

Volume of acid, HCl (Vₐ) = 30 mL

Molarity of acid, HCl (Mₐ) = 0.0400 M

Volume of base, KOH (V₆) =?

MₐVₐ / M₆V₆ = nₐ/n₆

0.04 × 30 / 0.997 × V₆ = 1/1

1.2 / 0.997 × V₆ = 1

Cross multiply

0.997 × V₆ = 1.2

Divide both side by 0.997

V₆ = 1.2 / 0.997

V₆ = 1.2 mL

Thus, the volume of the base, KOH needed to neutralize the acid is 1.2 mL.

7 0
3 years ago
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