Answer:
To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us use the thermodynamic definition of the Gibbs free energy and its relationship with Ksp as follows:

Thus, by combining them, we obtain:

Which is related to the general line equation:

Whereas:

It means that we answer to the blanks as follows:
To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.
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Carbon atoms are saturated with (surrounded by) Hydrogen atoms
<span>Sublimation: the substance changes directly from a solid to a gas without going through the liquid phase. Deposition: the substance changes directly from a gas to a solid without going through the liquid phase.</span>
<span>We would use the ideal gas equation. PV = NRT
No of moles of ag2o = 30/ 231.735 = 0.12944
The chemical reaction is given by
2 Ag2O = 4 Ag + O2
2* 0.12944 of Ag2O requires 0.12944 of O2
So we have P * 1 = 0.258 * 8.2 * 450
P = 952.02 atm</span>
Each mole of oxygen produces 1 mole of carbon dioxide.
Therefore, a given volume of oxygen will produce the same volume of carbon dioxide.
Volume of CO₂ produced is 3.75 liters at STP.