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neonofarm [45]
3 years ago
8

Which of the following gases would be most likely to experience ideal behavior at high pressures?

Chemistry
2 answers:
Delvig [45]3 years ago
4 0
D, <span>Monotonic gases, which have no inter molecular attractions are most suited as ideal gases </span><span />
Anuta_ua [19.1K]3 years ago
3 0

Answer:

The answer is D, just answered my test ;))))))))

Explanation:

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7. Convert 5.2 cm of magnesium (Mg) ribbon to mm of Mg ribbon.
Effectus [21]
<h3>Answer:</h3>

52 mm

<h3>Explanation:</h3>

We are given;

  • 5.2 cm of magnesium

Required to convert it to cm

We are going to use the appropriate conversion factor;

  • The units used to measure length include;

Kilometer(km)

10

Hectometer (Hm)

10

Decameter (dkm)

10

Meter(m)

10

Decimeter (dm)

10

Centimeter (cm)

10

Millimeter (mm)

Therefore; the appropriate conversion factor is 10mm/cm

Thus;

5.2 cm will be equivalent to;

= 5.2 cm × 10 mm/cm

= 52 mm

Therefore, the length of magnesium ribbon is 52 mm

7 0
3 years ago
Read 2 more answers
A helium filled ballon had a volume of 8.50 L on the ground at 20.0 C and a pressure of 750.0 Torr. After the ballon was release
Marrrta [24]

Answer:

V_2=12.1L

Explanation:

Hello!

In this case, according to the given data of volume, pressure and temperature, it is possible to infer this problem can be solved via the combined gas law:

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

Thus, regarding the question, we evidence we need V2, but first we make sure the temperatures are in Kelvins:

T_1=20+273=293K\\\\T_2=-40+273=233K

Then, we obtain:

V_2=\frac{P_1V_1T_2}{T_1P_2}\\\\V_2=\frac{0.987atm*8.50L*233K}{293K*0.550atm}\\\\V_2=12.1L

Best regards!

5 0
3 years ago
Which pieces of equipment would be used to measure the density of a solution?
Inessa05 [86]

Answer:

c I've taken chem 3 times

Explanation:

5 0
3 years ago
Read 2 more answers
How many joules are required for melting 12.8g of ice at 0 degrees Celsius?
tino4ka555 [31]

Answer:

4,270 Joules

Explanation:

The heat of fusion of water is 334 j/g. So, the equation would be (12.8 g)(334 j/g) which comes to 4,270 joules.

Written out that's just twelve point eight times three hundred and thirty four.

4 0
3 years ago
How many moles in 34.2 g of sulfur?
BigorU [14]
1.07 mol would be your answer
7 0
4 years ago
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