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neonofarm [45]
3 years ago
8

Which of the following gases would be most likely to experience ideal behavior at high pressures?

Chemistry
2 answers:
Delvig [45]3 years ago
4 0
D, <span>Monotonic gases, which have no inter molecular attractions are most suited as ideal gases </span><span />
Anuta_ua [19.1K]3 years ago
3 0

Answer:

The answer is D, just answered my test ;))))))))

Explanation:

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PLEASE HELP! MAJOR TEST GRADE! :(
Goshia [24]

Answer:

c

Explanation:

7 0
3 years ago
You drop a rock weighing 23.2 g into a graduated cylinder that contains 55 mL. The level
snow_lady [41]

Answer:

<h2>3.31 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 23.2 g

volume = final volume of water - initial volume of water

volume = 62 - 55 = 7 mL

We have

density =  \frac{23.2}{7}  \\  = 3.314285

We have the final answer as

<h3>3.31 g/mL</h3>

Hope this helps you

8 0
3 years ago
What effect does supercritical mass have on a nuclear reaction?
Ksju [112]
Supercritical mass results to an increase in the rate of fission. There is a chain reaction that will occur. Nuclear fission or explosion used in atomic bombs relies on supercritical mass. An atom splits into two, with each splitting into two pairs and so on, releasing energy in each step.
3 0
3 years ago
Read 2 more answers
One half of a balanced chemical equation is shown. 3Mg(OH)2 + 2H3PO4
nasty-shy [4]

Answer:

3Mg(OH)2 + 2H3PO4 = Mg3(PO4)2 + 2H3O

Explanation:

8 0
3 years ago
(6 points) Alice owns 20 grams of a radioactive isotope that has a half-life of ln(4) years. (a) Find an equation for the mass m
Cloud [144]

<u>Answer:</u> The equation to calculate the mass of remaining isotope is [A]=\frac{20}{10^{-0.217t}}

<u>Explanation:</u>

The equation used to calculate rate constant from given half life for first order kinetics:

t_{1/2}=\frac{0.693}{k}

where,

t_{1/2} = half life of the reaction = \ln 4=1.386yrs

Putting values in above equation, we get:

k=\frac{0.693}{1.386yrs}=0.5yrs^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}

where,

k = rate constant = 0.5yr^{-1}

t = time taken for decay process

[A_o] = initial amount of the sample = 20 grams

[A] = amount left after decay process =  ? grams

Putting values in above equation, we get:

0.5=\frac{2.303}{t}\log\frac{20}{[A]}

[A]=\frac{20}{10^{-0.217t}}

Hence, the equation to calculate the mass of remaining isotope is [A]=\frac{20}{10^{-0.217t}}

6 0
3 years ago
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