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dybincka [34]
4 years ago
15

Fog is an example of a

Chemistry
1 answer:
Crank4 years ago
6 0

Answer:

colloidal system liquid dispersed in gas.

You might be interested in
How many particles are in 2.50 moles of iron (II) chloride?
liq [111]

Answer:

<h2>1.505 × 10²⁴ particles</h2>

Explanation:

The number of particles in iron (II) chloride can be found by using the formula

<h3>N = n × L</h3>

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 2.5 × 6.02 × 10²³

We have the final answer as

<h3>1.505 × 10²⁴ particles</h3>

Hope this helps you

8 0
3 years ago
One way to account for the mass "lost" in a reaction that involves a gas would be to________.
sergiy2304 [10]

Answer:

Place the experiments on a scale

Explanation:

If you place two of the same experiments on a scale, and cover one with a cup, the one with the cup will "lose" mass, while the other won't, due to the cup being a "containment field" I guess you could call it.

5 0
3 years ago
Hydrogen bromide decomposes when heated to 437C according to the equation: 2HBr(g) H2(g) Br2(g). If the reaction starts with 2.1
iren [92.7K]

Answer:

<h3>the equilibrium constant of the decomposition of hydrogen bromide is 0.084</h3>

Explanation:

Amount of HBr dissociated

2.15 \ mole \times \frac{36.7}{100} \\\\=0.789 \ mole

                                  2HBr(g)        ⇆          H2(g)           +          Br2(g)

Initial Changes          2.15                             0                                0  (mol)

                                - 0.789                      + 0.395                     + 0.395 (mol)

At equilibrium        1.361                            0.395                         0.395 (mole)

Concentration        1.361 / 1                   0.395 / 1                      0.395 / 1

at equilibrium (mole/L)

K_c=\frac{[H_2][Br_2]}{[HBr]^2} \\\\=\frac{(0.395)(0.395)}{(1.361)^2} \\\\=\frac{0.156025}{1.852321} \\\\=0.084

<h3>Therefore, the equilibrium constant of the decomposition of hydrogen bromide is 0.084</h3>
6 0
3 years ago
Question 2 (Multiple Choice Worth 2 points)
faust18 [17]

Answer:

\pi r²  x h

Explanation:

A can is cylindrical in nature. Using the formula of the volume of the can, we can find this unknown volume.

The volume of cylinder is given as:

   Volume of a cylinder  = Area x height

  Volume of  a cylinder = \pi r²  x h

Therefore density of the can;

      Density  = \frac{mass}{volume}

6 0
3 years ago
A sample of 42 mL of carbon dioxide gas was placed in a piston in order to maintain a constant 101 kPa of pressure.
Lilit [14]

Answer:

The answer to your question is 33.4 ml

Explanation:

Data

volume 1 = V1 = 42 ml

temperature 1 = T1 = 20°C

temperature 2 = T2 = -60°C

Volume 2 = V2 = x

Process

1.- Convert celsius to kelvin

T1 = 20 + 273 = 293°K

T2 = -60 + 273 = 233°K

2.- Use the Charles' law to solve this problem

               \frac{V1}{T1} = \frac{V2}{T2}

Solve for V2

                V2 = \frac{V1T2}{T1}

3.- Substitution

               V2 = \frac{(42)(233)}{293}

4.- Simplification

                V2 = \frac{9786}{293}

5.- Result

                V2 = 33.4ml

3 0
3 years ago
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