Answer:
The criteria listed in order of importance are;
1) To be inflated in the event of a collision in order to protect the occupants of the front of the vehicle
2) To be able to withstand the load of the breaking force of the occupants in the front seat of the vehicle during a collision
3) To be relatively tough so as to resist being torn on impact with a sharp object
The constraints listed in order of importance are;
1) How is the model design able to sense a collision that requires the airbag to be inflated
2) The uncertainty of the load the airbag will withstand upon collision
3) The possible hazard that could be caused by the gas used to inflate the airbag
4) The usage/interaction tendency between the vehicle occupant and the airbag system
Explanation:
In order to produce an effective design, it is important to be able to foresee the possible deficiencies of an idea so as to be able to mitigate the problems before an actual incident happens.
Answer:
Hence, the wavelength of the photon associated is 1282 nm.
Explanation:
Answer:
Ksp = 2.74 x 10⁻⁵
Explanation:
The solubility equilibrium for Ca(OH)₂ is the following:
Ca(OH)₂(s) ⇄ Ca²⁺(aq) + 2 OH⁻(aq)
I 0 0
C + s + 2s
E s 2s
According to the ICE table, the expression for the solubility product constant (Kps) is:
Ksp = [Ca²⁺] x ([OH⁻])² = s x (2s)² = 4s³
Then, we calculate Ksp from the solubility value (s):
s = 0.019 M
⇒ Ksp = 4s³ = 4 x (0.019)³ = 2.74 x 10⁻⁵
0.300 M IKI represents the
concentration which is in molarity of a potassium iodide solution. This means
that for every liter of solution there are 0.300 moles of potassium iodide. Knowing
that molarity is a ratio of solute to solution.
By using a conversion factor:
100 ml x (1L / 1000 mL) x (0.300
mol Kl / 1 L) x (166.0g / 1 mol Kl) = 4.98 g
Therefore, in the first
conversion by simply converting the unit of volume to liter, Molarity is in L
where the volume is in liters. The next step is converted in moles from volume
by using molarity as a conversion factor which is similar to how density can be
used to convert between volume and mass. After converting to moles it is simply
used as molar mass of Kl which is obtained from periodic table to convert from
mole to grams.
In order to get the grams of IKI
to create a 100 mL solution of 0.600 M IKI, use the same formula as above:
100 ml x (1L / 1000 mL) x (0.600
mol Kl / 1 L) x (166.0g / 1 mol Kl) = 9.96 g
