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tangare [24]
3 years ago
13

What is the empirical formula for propene (C3H6)? C2H4 C4H8 C3H6 CH2

Chemistry
2 answers:
melamori03 [73]3 years ago
8 0

Answer:

C3H6

Explanation:

please mark me as brainlest

Alina [70]3 years ago
7 0

Explanation:

C3H6 <em>is </em><em>your</em><em> answer</em>

<em>pls</em><em> mark</em><em> above</em><em> guy</em><em> ans</em><em> as</em><em> brainliest</em>

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2A1 +3CL2, → 2AICI3 what is the reaction
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What kind of product is formed when a ketone reacts with a grignard reagent followed by protonation?
svet-max [94.6K]

c. a tertiary alcohol; when a ketone reacts with a grignard reagent followed by protonation a tertiary alcohol is formed.

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8 0
2 years ago
For the following reaction, KcKc = 255 at 1000 KK.
bonufazy [111]

Answer :

The equilibrium concentration of CO is, 0.016 M

The equilibrium concentration of Cl₂ is, 0.034 M

The equilibrium concentration of COCl₂ is, 0.139 M

Explanation :

The given chemical reaction is:

                           CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)

Initial conc.      0.1550      0.173           0

At eqm.          (0.1550-x)  (0.173-x)         x

As we are given:

K_c=255

The expression for equilibrium constant is:

K_c=\frac{[COCl_2]}{[CO][Cl_2]}

Now put all the given values in this expression, we get:

255=\frac{(x)}{(0.1550-x)\times (0.173-x)}

x = 0.139 and x = 0.193

We are neglecting value of x = 0.193 because equilibrium concentration can not be more than initial concentration.

Thus, we are taking value of x = 0.139

The equilibrium concentration of CO = (0.1550-x) = (0.1550-0.139) = 0.016 M

The equilibrium concentration of Cl₂ = (0.173-x) = (0.173-0.139) = 0.034 M

The equilibrium concentration of COCl₂ = x = 0.139 M

5 0
3 years ago
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