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Ira Lisetskai [31]
3 years ago
11

QUESTION 1 Find the remaining sides of a 30° -60°-90° triangle if the shortest side is 3.

Mathematics
2 answers:
Anton [14]3 years ago
7 0

Answer:

the other sides are 6 and 3√3

Step-by-step explanation:

Korvikt [17]3 years ago
7 0

Answer:

x = 6

Step-by-step explanation:

<u>Right Triangle</u>

We are given a right triangle whose shortest side has a length of 3 units. This side must be opposite to the smallest acute angle of 30°.

The triangle is shown in the figure attached.

The tangent ratio relates the opposite side with the adjacent side. The formula can be applied to the angle of 30° as follows:

\displaystyle \tan 30^\circ=\frac{\text{opposite leg}}{\text{adjacent leg}}

\displaystyle \tan 30^\circ=\frac{3}{y}

Solving for y:

\displaystyle y=\frac{3}{\tan 30^\circ}

Since:

\tan 30^\circ=\frac{1}{\sqrt{3}}

\displaystyle y=3\sqrt{3}

Now applying the sine to find the hypotenuse x:

\displaystyle \sin 30^\circ=\frac{\text{opposite leg}}{\text{hypotenuse}}

\displaystyle \sin 30^\circ=\frac{3}{x}

Solving for x:

\displaystyle x=\frac{3}{\sin 30^\circ}

Since:

\sin 30^\circ=\frac{1}{2}

\displaystyle x=\frac{3}{\frac{1}{2}}

x = 6

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