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scoray [572]
3 years ago
12

Identify the function shown in this graph

Mathematics
1 answer:
blagie [28]3 years ago
6 0

A  i think im not really sure im also thinking it might be B

You might be interested in
Need answer this urgent and fast
Karo-lina-s [1.5K]

Answer:

56

Step-by-step explanation:

Hey There!

so this is a parallelogram so opposite angles are congruent

So basically what i am saying is that angle P is congruent to angle R

So we need to solve for x

We know that angle P and angle Q are supplements meaning that they will add up to 180

so we setup the equation

180=3x+5+8x-12\\

step 1 combine like terms

3x+8x=11x\\5-12=-7

now we have

180=11x-7

step 2 add 7 to each side

180+7=187

-7+7 cancels out

now we have

187=11x

step 2 divide each side by 11

187/11=17

x=17

now we plug in 17 to (3x+5) to get the value of angle R

17x3=51

51+5=56

therefore m∠R = 56

5 0
2 years ago
Consider the parabola r​(t)equalsleft angle at squared plus 1 comma t right angle​, for minusinfinityless thantless thaninfinity
kodGreya [7K]

Given:-   r(t)=< at^2+1,t>  ; -\infty < t< \infty , where a is any positive real number.

Consider the helix parabolic equation :  

                                              r(t)=< at^2+1,t>

now, take the derivatives we get;

                                            r{}'(t)=

As, we know that two vectors are orthogonal if their dot product is zero.

Here,  r(t) and r{}'(t)  are orthogonal i.e,   r\cdot r{}'=0

Therefore, we have ,

                                  < at^2+1,t>\cdot < 2at,1>=0

< at^2+1,t>\cdot < 2at,1>=

                                              =2a^2t^3+2at+t

2a^2t^3+2at+t=0

take t common in above equation we get,

t\cdot \left (2a^2t^2+2a+1\right )=0

⇒t=0 or 2a^2t^2+2a+1=0

To find the solution for t;

take 2a^2t^2+2a+1=0

The numberD = b^2 -4ac determined from the coefficients of the equation ax^2 + bx + c = 0.

The determinant D=0-4(2a^2)(2a+1)=-8a^2\cdot(2a+1)

Since, for any positive value of a determinant is negative.

Therefore, there is no solution.

The only solution, we have t=0.

Hence, we have only one points on the parabola  r(t)=< at^2+1,t> i.e <1,0>




                                               




6 0
3 years ago
I need help? can anyone help
erica [24]
I think it’s 5 but don’t get mad if it’s wrong
7 0
3 years ago
How many 1/5 inch pieces can be cut from a sting 8 inches long
Snezhnost [94]

40 pieces

8/1 : 1/5   = 8/1*5/1   = 40/1  = 40

Another method :

1/5 = 0.2

8/0.2 = 40

5 0
2 years ago
There are 36 students in Mrs.Keatons's sixth grade class. If 5/12 of her students are girls, how many girls in the class?
murzikaleks [220]
There are 15 girls because 12 x 3 = 36 and 5 x 3 = 15
6 0
3 years ago
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