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PolarNik [594]
2 years ago
14

Do I multiply these fractions or how do I get the simplified answer

Mathematics
1 answer:
timama [110]2 years ago
6 0

Answer:

Step-by-step explanation:

you have to add all the fractions to find the perimeter

10 1/7+10 1/7= 20 2/7 (width)

20 2/7+35 3/7(length) =55 5/7

12 2/7+12 2/7=24 4/7

55 5/7+24 4/7= 79 9/7=80 2/7

80 2/7+ 15 3/14+ 24 1/14= 562/7+ 213/14+337/14= (1124+213+337)/14

=1674/14=119 8/14= 119 4/7

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3 years ago
Would each of them be able to be the side lengths of a triangle?
ratelena [41]
Pythagoras Theorem:
hipotenuse²=leg₁²+leg₂²

First posible triangle:
hypotenuse=13    (13²=169)
leg₁=12                ( 12²=144)
leg₂=5                  (5²=25)

13³=144 + 25


Answer:can be side lengths of a triangle

Second triangle:
 hypotenuse=12.6    (12.6²=158.76)
leg₁=6.7                ( 6.7²=44.89)
leg₂=6.5                  (6.5²=42.25)

leg₁²+leg₂²=44.89+42.25=87.14≠158.76

Answer: cannot be side lenghts of a triangle.

third triangle:
hypotenuse=13    (13²=169)
leg₁=12                ( 12²=144)
leg₂=11                  (11²=121)

leg₁²+leg₂²=144+121=265≠169

Answer: cannot be side lenghts of a triangle.

fourth triangle:
hypotenuse=13   (13²=169)
leg₁=6                ( 6²=36)
leg₂=4                  (4²=16)

leg₁²+leg₁²=36+16=52≠169

Answer: cannot be side lenghts of a triangle.
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|90-(-20)|
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110 degrees celsius 
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