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fgiga [73]
3 years ago
13

The melting point of substance X is -20 degrees Celsius and the boiling point is 90 degrees Celsius. How many Celsius degrees ar

e there between the melting point and the boiling point?
20 degrees C
70 degrees C
90 degrees C
110 degrees C
Mathematics
2 answers:
Marat540 [252]3 years ago
8 0

Answer:

The answer is 110 degrees C.

Step-by-step explanation:

The melting point of substance X is -20 degrees Celsius and the boiling point is 90 degrees Celsius.

To find the difference between the degrees, we will subtract the values.

So, the difference between these points will be =

90-(-20)

= 90+20=110

The answer is 110 degrees C

Kazeer [188]3 years ago
3 0
To find the distance between 2 numbers you must take the absolute value of the difference

|90-(-20)|
|110|
110

110 degrees celsius 
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In each muffin there are 1.53oz

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The first step is to get the weight of just one muffin. If the package contains six muffins we must divide the total weight by six.

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Now, the problem says that blueberry high-fiber muffins contain 51 % dietary fiber by mass, which means that we must calculate the 51% of 3oz. We must take into account that 51% equals 51/100 which is 0.51. The equation would be:

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6 0
4 years ago
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y

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For this problem the slope is:

m

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m

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m

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Now, selecting one of the points we can use the point slope formula to find the equation.

The point slope formula is:

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Substituting one of our points gives:

y

−

−

1

=

2

(

x

−

0

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y

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x

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y

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x

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1

y

+

0

=

2

x

−

1

y

=

2

x

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1

Answer linky

=

2

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1

Explanation:

First, we need to determine the slope of the line. The formula for determining the slope of a line is:

m

=

y

2

−

y

1

x

2

−

x

1

where

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is the slope and the x and y terms are for the points:

(

x

1

,

y

1

)

and

(

x

2

,

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2

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m

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+

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2

m

=

4

2

m

=

2

Now, selecting one of the points we can use the point slope formula to find the equation.

The point slope formula is:

y

−

y

1

=

m

(

x

−

x

1

)

Substituting one of our points gives:

y

−

−

1

=

2

(

x

−

0

)

y

+

1

=

2

x

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y

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0

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