Use the digits 3,5,9 and 4 only once to make 2 addends whose sum is between 100 and 110.

Mathematics

2 answers:

Georgia [21]3 years ago

6 0

Use the digits 3,5,9,and 4 only once to make 2 addends whose sum is between 100 and 110

vesna_86 [32]3 years ago

5 0

3,5,9 and 4 only once to make 2 addends whose sum is between 100 and 110

53 + 49 = 102

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Last year, Michael opened an investment account with $5400. At the end of the year, the amount in the account had decreased by 2

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He would have $4131 left from $5400 with a decrease with 23.5%

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3 years ago

Let P = 0.50.30.50.7 be the transition matrix for a Markov chain with two states. Let x0 = 0.50.5 be the initial state vector fo

pav-90 [236]

Answer:

Probability distribution vector = $\left(\begin{array}{c}0.375\\ 0.625 \end{array} \right)$

Step-By-Step Explanation

If $P=\left(\begin{array}{cc}0.5&0.3\\ 0.5&0.7 \end{array} \right)$ is the transition matrix for a Markov chain with two states.

$x_{0}=\left(\begin{array}{c}0.5\\ 0.5 \end{array} \right)$ be the initial state vector for the population.

$X_{1}=P x_{0}=\left(\begin{array}{cc}0.5&0.3\\ 0.5&0.7 \end{array} \right) \left(\begin{array}{c}0.5\\ 0.5 \end{array} \right) =\left(\begin{array}{c}0.4\\ 0.6 \end{array} \right)$

$X_{2}=P^{2} x_{0}=\left(\begin{array}{c}0.38\\ 0.62 \end{array} \right)$

$X_{3}=P^{3} x_{0}=\left(\begin{array}{c}0.38\\ 0.62 \end{array} \right)$

$X_{30}=P^{30} x_{0}=\left(\begin{array}{c}0.37499\\ 0.625 \end{array} \right)$

In the long run, the probability distribution vector Xm approaches the probability distribution vector $\left(\begin{array}{c}0.375\\ 0.625 \end{array} \right)$ .

This is called the steady-state (or limiting,) distribution vector.

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3 years ago

Please Help ASAP! Simplify roots of negative numbers. Express your answer in simplified form.

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Answer:

$3i\sqrt2$

Step-by-step explanation:

We can rewrite the square root of negative 18 as $\sqrt{18} \cdot\sqrt{-1}$ . We can evaluate these two quantities separately. The square root of 18 can be factored to get 3 squared times 2. We can take the 3 out to get $3\sqrt2$ . Now, the square root of negative one can be rewritten as $i$ , so this is equal to $3i\sqrt2$