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3 years ago

I really need helppppppp on yhis wb homework

Mathematics

1 answer:

Slav-nsk [51]3 years ago

4 0

You'll have to do 9.33 plus 1.32 seconds

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I need help fast ....

Cloud [144]

Since x=-10, plug that into the equation.

f(x) = 2(-10) + 11
= -20 + 11
y = -9

So the ordered pair in (x,y) terms is (-10,-9).

4 0

3 years ago

Please help assaaaappp

inessss [21]

5k^2 = 25 ^ 3 = 15625
5k^6 = 15625
Hope this helps

7 0

3 years ago

Find the values of x when y=1

kirill [66]

Answer:

$x=1+\sqrt{5}, 1-\sqrt{5}$

Step-by-step explanation:

$x^{2} -2x-4=0$
$(x-1)^{2} -1-4=0$
$(x-1)^{2} -5=0$
$(x-1)^{2} =5$
$x-1=\sqrt{5} ,-\sqrt{5}$
$x=1+\sqrt{5} , 1-\sqrt{5}$

FINAL ANSWER

$x=1+\sqrt{5} , 1-\sqrt{5}$

In Decimal Form (Rounded to 3 significant figures)

x≈-1.24, 3.24

6 0

3 years ago

Read 2 more answers

NO SCAM LINKS. please reply ASAP PLEASEEEE

natulia [17]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Find an equation of the circle that has center (-4,3) and passes through (6,-4).

kumpel [21]

Answer:

$(x+4)^2+(y-3)^2=149$

Step-by-step explanation:

The equation of a circle is $(x-h)^2+(y-k)^2=r^2$ where $(h,k)$ is the center of the circle and $r$ is the radius of the circle.

Given that $(h,k)\rightarrow(-4,3)$ and it passes $(6,-4)$ , their distance between each other must the radius of the circle, so we can use the distance formula to find the radius:

$d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}\\\\d=\sqrt{(-4-3)^2+(6-(-4))^2}\\\\d=\sqrt{(-7)^2+10^2}\\\\d=\sqrt{49+100}\\\\d=\sqrt{149}$

Therefore, if the length of the radius is $r=\sqrt{149}$ units, then $r^2=149$ , making the final equation of the circle $(x+4)^2+(y-3)^2=149$

5 0

3 years ago