Answer:
Practice started at 1:55 pm.
Step-by-step explanation:
At the 3/4 marker, the rider can collect a green ribbon and a blue ribbon.
Because 3/4 is the 3rd stop for a blue ribbon and 3/4 is the 6th stop for a green ribbon.
The diagonal fencing will be the hypotenuse of a right triangle with sides 120yds long so:
h=√2(120^2))
h=√28800 yd
And the surrounding fencing will just be four times the side length of 120yds so:
s=480yd
So the total fencing needed is:
f=480+√28800 yards
f≈649.71 yd (to nearest hundredth of a yard) which is
f≈650 yds (to nearest whole yard)
But, I wasn't sure, if they just want the diagonal fencing needed then it is just:
f=√28800
f≈170 yds (to nearest yard)
Answer:
C=24π
Step-by-step explanation:
C=2πr
C=2π12
C=24π
≈75.39
