Use ideal gas equation: pV = nRT
Now pass n to mass: n = mass / MM .... [MM is the molar mass]
pV = [mass/MM]*RT =>mass/V = [p*MM] / RT and mass / V = density
p= 130 kPa = 130,000 Pa = 130,00 joule / m^3
T = 10.0 ° + 273.15 = 283.15 k
MM of sulfur (S) = 32 g/mol = 32000 kg/mol
density = 130,000 Pa * 32000kg/mol / [8.31 joule / mol*k * 283.15 k] = 1.77*10^6 kg/m^3 = 1.77 g/L ≈ 1.8 g/L
Then, I do not get any of the option choices.
Is it possbile that the pressure is 13.0 kPa instead 130. kPa? If so the answer would be 18 g/L
Note that the mass is not used. You do not need it unless you are asked for the volume, which is not the case.
As, Te, Ge, Si, Sb, B, Po, At, Se.
To solve the equation for Mass, rearrange the equation by multiplying both sides timesVolume in order to isolate Mass, then plug in your known values (Density and Volume). Then solve for Mass.
Answer:
0.113 M
Explanation:
The reaction that takes place is:
- NaHCO₃ + HCl →NaCl + CO₂ + H₂O
First we convert 0.3967 g of NaHCO₃ into moles, using its molar mass:
- 0.3967 g ÷ 84 g/mol = 4.72x10⁻³ mol NaHCO₃
As 1 mol of NaHCO₃ reacts with 1 mol of HCl, in 41.77 mL of the HCl solution there were 4.72x10⁻³ moles of HCl.
With the <em>calculated number of moles and the given volume </em>we <u>calculate the concentration of the solution</u>:
- Converting 41.77 mL ⇒ 41.77 mL / 1000 = 0.04177 L
- Concentration = 4.72x10⁻³ mol / 0.04177 L = 0.113 M
