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malfutka [58]
3 years ago
12

Derive Boyle's law.i'll mark the brainliest for the answer​

Chemistry
1 answer:
MArishka [77]3 years ago
6 0

Answer:

According to Boyle's Law, an inverse relationship exists between pressure and volume. ... The relationship for Boyle's Law can be expressed as follows: P1V1 = P2V2, where P1 and V1 are the initial pressure and volume values, and P2 and V2 are the values of the pressure and volume of the gas after change.  

<em>Hope that helps! :)</em>

<em></em>

<em>-Aphrodite</em>

Explanation:

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4
matrenka [14]

Answer:

Yes.

Explanation:

Yes, this difference of readings will definitely affect the results of the experiment as well as the E values because the readings taken by both students are different from one another. There is a fault in one of the thermometer because both shows different readings of temperature of the same solution. This will affect the overall experiment and due to this error, we are unable to tell that which one reading is correct so the answer is uncertain or unsure.

5 0
2 years ago
Select the correct answer. Which is a chemical change? A. water boiling B. wood burning C. glass breaking D. ice melting E. mold
asambeis [7]

B. wood burning is a chemical change.

4 0
3 years ago
Read 2 more answers
How many doubtful digit(s) is/are allowed in any measured quantity?
Mnenie [13.5K]

Answer:

zero

Explanation:

I I think one should be so accurate with measurements and experiments

3 0
3 years ago
The cell potential of a redox reaction occurring in an electrochemical cell under any set of temperature and concentration condi
avanturin [10]

Answer : The actual cell potential of the cell is 0.47 V

Explanation:

Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

The given redox reaction is :

Ni^{2+}(aq)+Zn(s)\rightarrow Ni(s)+Zn^{2+}(aq)

The balanced two-half reactions will be,

Oxidation half reaction : Zn\rightarrow Zn^{2+}+2e^-

Reduction half reaction : Ni^{2+}+2e^-\rightarrow Ni

The expression for reaction quotient will be :

Q=\frac{[Zn^{2+}]}{[Ni^{2+}]}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

Q=\frac{(0.0141)}{(0.00104)}=13.6

The value of the reaction quotient, Q, for the cell is, 13.6

Now we have to calculate the actual cell potential of the cell.

Using Nernst equation :

E_{cell}=E^o_{cell}-\frac{RT}{nF}\ln Q

where,

F = Faraday constant = 96500 C

R = gas constant = 8.314 J/mol.K

T = room temperature = 316 K

n = number of electrons in oxidation-reduction reaction = 2 mole

E^o_{cell} = standard electrode potential of the cell = 0.51 V

E_{cell} = actual cell potential of the cell = ?

Q = reaction quotient = 13.6

Now put all the given values in the above equation, we get:

E_{cell}=0.51-\frac{(8.314)\times (316)}{2\times 96500}\ln (13.6)

E_{cell}=0.47V

Therefore, the actual cell potential of the cell is 0.47 V

4 0
3 years ago
When a certain powder is mixed into a solution of silver nitrate, a white precipitate forms. When the powder is added to a solut
atroni [7]

Answer:

Ammonium chloride

Explanation:

The powder is:- Ammonium chloride

When mixed with silver nitrate, white prescipitate of silver chloride is formed as:-

NH_4Cl+AgNO_3\rightarrow NH_4NO_3+AgCl

When mixed with sodium hydroxide, ammonia gas is formed which has noxious order.

NH_4Cl +NaOH\rightarrow NH_3 + H_2O + NaCl

Ammonia gas on reaction with nickel (II) hydroxide forms deep blue colored complex as shown below:-

Ni(OH)_2(s) + 6NH_3(aq)\rightarrow [Ni(NH_3)_6]^{2+}(aq) + 2OH^{-}(aq)

5 0
3 years ago
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