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AnnyKZ [126]
3 years ago
12

Hey please answer this thanks.

Chemistry
1 answer:
Aleks04 [339]3 years ago
6 0

Explanation:

Percentage composition of oxygen = (80/134) * 100% = 59.7%.

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Question 5 of 10
pychu [463]
The answer is D. S2O6
4 0
3 years ago
A sample compound contains 5.723g Ag, 0.852g S and 1.695g O. Determine its empirical formula.
Lubov Fominskaja [6]

Answer:

Ag_2SO_4

Explanation:

Formula for the calculation of no. of Mol is as follows:

mol=\frac{mass\ (g)}{molecular\ mass}

Molecular mass of Ag = 107.87 g/mol

Amount of Ag = 5.723 g

mol\ of\ Ag=\frac{5.723\ g}{107.87\ g/mol} =0.05305\ mol

Molecular mass of S = 32 g/mol

Amount of S = 0.852 g

mol\ of\ S=\frac{0.852\ g}{32\ g/mol} =0.02657\ mol

Molecular mass of O = 16 g/mol

Amount of O = 1.695 g

mol\ of\ O=\frac{1.695\ g}{16\ g/mol} =0.10594\ mol

In order to get integer value, divide mol by smallest no.

Therefore, divide by 0.02657

Ag, \frac{0.05305}{0.02657} \approx 2

S, \frac{0.02657}{0.02657} \approx 1

O, \frac{0.10594}{0.02657} \approx 4

Therefore, empirical formula of the compound = Ag_2SO_4

7 0
3 years ago
Read 2 more answers
Using the periodic table, determine the ion charges of the following families of elements if valence electrons were removed or a
kogti [31]

Group I=1+

Group VI=-2

Group III=3+

6 0
3 years ago
Read 2 more answers
What model would represent individual atoms of different types that repeat to form a crystal
Law Incorporation [45]

Answer:

Although atoms are the smallest units that can be found in all matter, these atoms have a complex structure when experimentally analyzed. In order to understand almost all concepts in chemistry, it is essential to clearly understand the basic structure of an atom. Crystals are solid compounds made out of a number of atoms or molecules. There are particular arrangements in crystals. These arrangements are called crystal structures. Examining the crystal structure is very important in determine

Explanation:

7 0
2 years ago
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Ava threw a hamster at her sister the other day she used 12N of force to accelerate the hamster at 8m/s2.what was the mass of th
xenn [34]

<u>We are given:</u>

The force applied on the poor hamster (F) = 12 N

Acceleration of the poor Hamster (a) = 8 m/s²

<u>Solving for the mass of the Poor Hamster:</u>

From newton's second equation of motion, we know that:

F = ma

<em>replacing the given values</em>

12 = 8 * m

m = 12/8 kg

m = 3/2 kg

The poor Hamster weighs 3/2 kg

8 0
2 years ago
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