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3 years ago

20/4+8/3 answer? I don’t get the question

Mathematics

2 answers:

Neko [114]3 years ago

8 0

Answer:

To Acquire

➠The Value of 20/4+8/3

➠Firstly ,we need to find out the LCM of the denominators

➠12

Now,

➠We've to Multiply the numerator with the number which is divisible by the resulting LCM from the respective denominator

➠just like ,here ,12/4 = 3 so we'll Multiply 3 by the numerator of 4 i.e 20 => 20*3 = 60

We'll apply the same thing with the other one

➠12/3=4 => 4*8 = 32

➠Now ,we will add the resulting numerators and will keep it in a fraction with the denominator = LCM of 4&3=12

➠60+32/12 

➠92/12

➠ 46/6

➠23/3

Bumek [7]3 years ago

3 0

Answer:

Step-by-step explanation:

if you need to add 2 fractions

20/4+ 8/3

common denominator is 12

60/12+32/12=92/12= 7 8/12 =7 2/3

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3 years ago

Jason inherited a piece of land from his great-uncle. Owners in the area claim that there is a 45% chance that the land has oil.

oksian1 [2.3K]

Answer:

0.36 = 36% probability that the land has oil and the test predicts it

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

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This means that $P(A) = 0.45$

He buys a kit that claims to have an 80% accuracy rate of indicating oil in the soil.

This means that $P(B|A) = 0.8$

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This is $P(A \cap B)$ . So

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

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3 years ago

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Answer:

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3 years ago

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Answer: 0.002718

Step-by-step explanation:

Given : The population mean annual salary for environmental compliance specialists is about $62,000.

i.e. $\mu=62000$

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$\sigma=6200$

Let x be the random variable that represents the annual salary for environmental compliance specialists.

Using formula $z=\dfrac{x-\mu}{\dfrac{\sigma}{\sqrt{n}}}$ , the z-value corresponds to x= 59000 will be :

$z=\dfrac{59000-62000}{\dfrac{6200}{\sqrt{32}}}\approx\dfrac{-3000}{\dfrac{6200}{5.6568}}=-2.73716129032\approx-2.78$

Now, by using the standard normal z-table , the probability that the mean salary of the sample is less than $59,000 :-

$P(z$

Hence, the probability that the mean salary of the sample is less than $59,000= 0.002718

3 0

3 years ago