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Vsevolod [243]
3 years ago
7

20/4+8/3 answer? I don’t get the question

Mathematics
2 answers:
Neko [114]3 years ago
8 0

Answer:

To Acquire

➠<em><u>T</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>Value</u></em><em><u> </u></em><em><u>of </u></em><em><u>2</u></em><em><u>0</u></em><em><u>/</u></em><em><u>4</u></em><em><u>+</u></em><em><u>8</u></em><em><u>/</u></em><em><u>3</u></em>

<em><u>➠</u></em><em><u>F</u></em><em><u>i</u></em><em><u>r</u></em><em><u>s</u></em><em><u>t</u></em><em><u>l</u></em><em><u>y</u></em><em><u> </u></em><em><u>,</u></em><em><u>we </u></em><em><u>need </u></em><em><u>to </u></em><em><u>find </u></em><em><u>out </u></em><em><u>the </u></em><em><u>LCM </u></em><em><u>of </u></em><em><u>the </u></em><em><u>denominators</u></em>

<em><u>➠</u></em><em><u>1</u></em><em><u>2</u></em>

<em><u>Now,</u></em>

<em><u>➠</u></em><em><u>W</u></em><em><u>e</u></em><em><u>'</u></em><em><u>v</u></em><em><u>e</u></em><em><u> </u></em><em><u>to </u></em><em><u>Multiply</u></em><em><u> </u></em><em><u>the </u></em><em><u>numerator</u></em><em><u> </u></em><em><u>with</u></em><em><u> </u></em><em><u>the </u></em><em><u>number</u></em><em><u> </u></em><em><u>which </u></em><em><u>is </u></em><em><u>divisible</u></em><em><u> </u></em><em><u>by </u></em><em><u>the </u></em><em><u>resulting</u></em><em><u> </u></em><em><u>LCM </u></em><em><u>from </u></em><em><u>the </u></em><em><u>respective</u></em><em><u> </u></em><em><u>denominator</u></em>

<em><u>➠</u></em><em><u>j</u></em><em><u>u</u></em><em><u>s</u></em><em><u>t</u></em><em><u> </u></em><em><u>like </u></em><em><u>,</u></em><em><u>here </u></em><em><u>,</u></em><em><u>1</u></em><em><u>2</u></em><em><u>/</u></em><em><u>4</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>3</u></em><em><u> </u></em><em><u>so </u></em><em><u>we'll </u></em><em><u>Multiply</u></em><em><u> </u></em><em><u>3</u></em><em><u> </u></em><em><u>by </u></em><em><u>the </u></em><em><u>numerator</u></em><em><u> </u></em><em><u>of </u></em><em><u>4</u></em><em><u> </u></em><em><u>i.e </u></em><em><u>2</u></em><em><u>0</u></em><em><u> </u></em><em><u>=</u></em><em><u>></u></em><em><u> </u></em><em><u>2</u></em><em><u>0</u></em><em><u>*</u></em><em><u>3</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>6</u></em><em><u>0</u></em>

<em><u>We'll</u></em><em><u> </u></em><em><u>apply </u></em><em><u>the </u></em><em><u>same </u></em><em><u>thing</u></em><em><u> </u></em><em><u>with</u></em><em><u> </u></em><em><u>the </u></em><em><u>other</u></em><em><u> </u></em><em><u>one</u></em>

<em><u>➠</u></em><em><u>1</u></em><em><u>2</u></em><em><u>/</u></em><em><u>3</u></em><em><u>=</u></em><em><u>4</u></em><em><u> </u></em><em><u>=</u></em><em><u>></u></em><em><u> </u></em><em><u>4</u></em><em><u>*</u></em><em><u>8</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>3</u></em><em><u>2</u></em>

<em><u>➠</u></em><em><u>N</u></em><em><u>o</u></em><em><u>w</u></em><em><u> </u></em><em><u>,</u></em><em><u>we </u></em><em><u>will </u></em><em><u>add </u></em><em><u>the </u></em><em><u>resulting</u></em><em><u> </u></em><em><u>numerators </u></em><em><u>and</u></em><em><u> </u></em><em><u>will </u></em><em><u>keep </u></em><em><u>it </u></em><em><u>in </u></em><em><u>a </u></em><em><u>fraction</u></em><em><u> </u></em><em><u>with </u></em><em><u>the </u></em><em><u>denominator </u></em><em><u>=</u></em><em><u> </u></em><em><u>LCM </u></em><em><u>of </u></em><em><u>4</u></em><em><u>&</u></em><em><u>3</u></em><em><u>=</u></em><em><u>1</u></em><em><u>2</u></em>

<em><u>➠</u></em><em><u>6</u></em><em><u>0</u></em><em><u>+</u></em><em><u>3</u></em><em><u>2</u></em><em><u>/</u></em><em><u>1</u></em><em><u>2</u></em><em><u> </u></em>

<em><u>➠</u></em><em><u>9</u></em><em><u>2</u></em><em><u>/</u></em><em><u>1</u></em><em><u>2</u></em>

➠ <em><u>46/</u></em><em><u>6</u></em>

➠<em><u>2</u></em><em><u>3</u></em><em><u>/</u></em><em><u>3</u></em>

<h2><em><u>➠</u></em><em><u>7</u></em><em><u> </u></em><em><u> </u></em><em><u>⅔</u></em></h2>
Bumek [7]3 years ago
3 0

Answer:

Step-by-step explanation:

if you need to add 2 fractions

20/4+ 8/3

common denominator is 12

60/12+32/12=92/12= 7 8/12  =7 2/3

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HEEEEEEEEEEEEEEEEEEEEEEEELLLLLLLLP I BEG U! <br><br> BRAINLIEST FOR FIRST AND CORRECT ANSWER.
Tresset [83]
The answer to this question is 99/4, or 24.75, or 24 3/4.
They are all the same answer


I hope this helps!!!!!! 
3 0
3 years ago
Read 2 more answers
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