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Vlada [557]
3 years ago
5

8/12 = 2/9 What is the answer hurry please due today

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
3 0

Answer:

1/3

Step-by-step explanation:

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Question 9 (3 points)
Mila [183]

From the dot plot, we have that 90.91% of the students have 5 or more vowels in their first and last  names.

---------------------

The dot plot states that:

  • 2 students have 4 vowels in their first and last name.
  • 3 students have 5 vowels.
  • 8 students have 6 vowels.
  • 9 students have 7 vowels.

Then:

  • Total of 2 + 3 + 8 + 9 = 22 students.
  • 3 + 8 + 9 = 20 have or more vowels.

p = \frac{20}{22} \times 100\% = 90.91\%

90.91% of the students have 5 or more vowels in their first and last  names.

A similar problem is given at brainly.com/question/14354536

5 0
3 years ago
Please help!!!! I need this answer fast
Phantasy [73]

Answer:

sin S = 20/ 25

cos S = 15 / 20

tan S = 20/15

8 0
3 years ago
Explain how knowing 50×4 = 200 helps you find 500 × 400​
Leto [7]

Well, 50 x 4 = 200,  so just keep adding 0's!

50 x 4= 200

50 x 40 = 2,000

50 x 400 = 20,000

500 x 400 = 200,000

<em>Hope helps!-Aparri</em>

3 0
4 years ago
Read 2 more answers
A landscaping company has been commissioned to design a triangular flower bed for a mall
Deffense [45]

Answer:

A=b(1/2b-1)

112ft^2

Step-by-step explanation:

-Write the equation in factored form: A= b (1/2 b -1 )

-Supposed the base of the flower bed is 16 feet. What will the area be:

b=16 feet

Formula is A=1/2(1/2b-1)

Replace the b with 16

A=1/2 (16)^2 - 16

A=1/2 (256)-16

A=256/2 - 16

A=128-16

A=112 ft^2

The area will be 112 ft^2

3 0
3 years ago
Please help i don't know what I'm doing!!! :( multiply and simplify cot x( sin x - sec x)
fgiga [73]

Answer:

  cos(x) -csc(x)

Step-by-step explanation:

It is helpful to know the relations between the trig functions:

  \cot{x}=\dfrac{\cos{x}}{\sin{x}}\\\\\sec{x}=\dfrac{1}{\cos{x}}\\\\\csc{x}=\dfrac{1}{\sin{x}}

__

Then the given expression can be simplified as follows:

  \cot{x}(\sin{x}-\sec{x})=\dfrac{\cos{x}}{\sin{x}}\left(\sin{x}-\dfrac{1}{\cos{x}}\right)=\cos{x}-\dfrac{1}{\sin{x}}\\\\=\boxed{\cos{x}-\csc{x}}

6 0
3 years ago
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