Answer:
x ≥ 7/2
Step-by-step explanation:
8x - 3 ≥6x + 4
8x - 6x ≥ 4 + 3
2x ≥ 7
x ≥ 7/2
Step-by-step explanation:
arccos(sin(5π/4))
= arccos(sin(-π/4))
= arccos(-√2/2)
= 3π/4.
<u>Answer: </u>
After simplifying 63÷4+2 ×9(32 ×8-17 ×4 ) we get 3399.75
<u>Solution:
</u>
We need to simplify 63÷4+2 ×9(32 ×8-17 ×4 ).
We will be using BODMAS rule to solve. According the BODMAS rule, Bracket has the highest precedence, than comes division, multiplication, addition and at last subtraction.
On solving bracket first, applying multiplication and then subtraction we get
=63÷4+2 ×9(256-68 )
=63÷4+18 ×188
Now doing division first we get

As multiplication have precedence over addition, we get


Hence after simplifying 63÷4+2 ×9(32 ×8-17 ×4 ) we get 3399.75
Let the number of nickels found be n, the number of dimes be d and the number of quarters be q.
i) "you have twice as many quarters as dimes and 42 coins in all."
means that 2d=q, and n+d+q=42
we can reduce the number of unknowns by substituting q with 2d:
n+d+q=42
n+d+2d=42
n+3d=42
We can write all n, d and q in terms of d as follows:
there are n=42-3d nickels, d dimes and q=2d quarters.
ii) In total there are $6.60 dollars,
1 nickel = 5 cent = $0.05
1 dime = 10 cent = $0.1
1 quarter = 25 cent = $0.25
thus
(42-3d)*0.05 + d*0.1 +2d*0.25= $6.60
2.1 - 0.15d+0.1d+0.5d=6.60
2.1+0.45d=6.6
0.45d=6.6-2.1=4.5
d=4.5/0.45=10
iii)
so, there are 10 dimes, 2d=2*10=20 quarters and 42-3d=42-3*10=12 nickels.
Answer: 10 dimes, 20 quarters, 12 nickels
Answer:
Answer 19:- x = 5
Answer 20:- x = 11
Step-by-step explanation:
Answer 19:-
2x + 10 = 20
2x = 10
x = 5
Answer 20:-
80 + 20x = 300
20x = 220
x = 11