Answer:
The required probability is 0.1.
Step-by-step explanation:
red balls = 3
yellow balls = 2
blue balls = 5
Selected balls = 5
Number of elemnets in sample space = 10 C 5 = 1260
Ways to choose 1 red ball and 4 other colours = (3 C 1 ) x (7 C 4) = 105
Ways to choose 5 balls of other colours = 7 C 5 = 21
So, the probability is
Ok so I did 25 divided by 2 I got 12.5 and 26 divided by 3 and got 8.6 so the best deal would be 8.6 for part A .
Give me a picture of the problem and i will solve it