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Margaret [11]
3 years ago
12

Find the next three terms of each geometric sequence.

Mathematics
1 answer:
wel3 years ago
4 0
I tried subtraction addition multiplication and division and I am still very confused on this
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100 POINTS 10 QUESTIONS PLEASE HELP PICTURES BELOW PLEASE SPECIFY WHICH QUESTION YOU ARE ANSWERING
Semenov [28]

Answer:

The answers are \frac{2}{5}, \frac{1}{4}, \frac{1}{10}, \frac{5}{2}, \frac{5}{8}, \frac{4}{1}, \frac{8}{5}, and \frac{10}{1}.

Step-by-step explanation:

Proportions are fractions that can be made by using the given numbers, which in this case are 2, 5, 8, and 20. Let's pair each one with the other three and then simplify if possible.

First, let's begin with 2:

\frac{2}{5} = \frac{2}{5}

\frac{2}{8} = \frac{1}{4}

\frac{2}{20} = \frac{1}{10}

Then, let's do 5:

\frac{5}{2} = \frac{5}{2}

\frac{5}{8} = \frac{5}{8}

\frac{5}{20} = \frac{1}{4}

Note that we already have \frac{1}{4}, so we do not need to include an additional one.

Now, let us do 8:

\frac{8}{2} = \frac{4}{1}

\frac{8}{5} = \frac{8}{5}

\frac{8}{20} = \frac{2}{5}

See how we already have \frac{2}{5}, so we won't have to include that as well.

Finally, let's do 20:

\frac{20}{2} = \frac{10}{1}

\frac{20}{5} = \frac{4}{1}

\frac{20}{8} = \frac{5}{2}

Now see that we already have both \frac{4}{1} and \frac{5}{2}, so we won't have to include both of them, as they are both extras.

Hence, the answers are \frac{2}{5}, \frac{1}{4}, \frac{1}{10}, \frac{5}{2}, \frac{5}{8}, \frac{4}{1}, \frac{8}{5}, and \frac{10}{1}.

<h2><u><em>PLEASE MARK AS BRAINLIEST!!!!!</em></u></h2>
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3 years ago
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A rental car company charges $15/day for a rental car plus 20¢ for every mile driven that day. Which equation models the relatio
nikdorinn [45]
<span>R=15d+0.20R=15d+0.20 is the answer</span>
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Mr .scoot filled an above ground pool with water . He filled it to a height of 5 ft in 25 hours. What was the Raye at which he f
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In guessing 5 ft an hour
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How do you do this question?
vivado [14]

Answer:

-1

Step-by-step explanation:

dy/dt = y² − 1 = (y + 1) (y − 1)

At t = 0, y = 0, and dy/dt = -1.  Therefore, y is initially decreasing.

As y decreases, dy/dt increases.  When y = -1, dy/dt = 0 and changes signs from negative to positive.

As y increases above -1, dy/dt again becomes negative.  So y continues to approach -1 as t approaches infinity.

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Find the y intercept of the line above.
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The y-intercept is (0, 2), because it's the spot where the line crosses the y-axis. The other point showed on the graph is the x-intercept..
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