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2 years ago

Can someone help me lol

Mathematics

1 answer:

Ivenika [448]2 years ago

4 0

Answer: 51
80+49=129
180-129= 51

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Consider the formula for the slope between two coordinate points, m, shown below. Which of the following equations is equivalent

o-na [289]

Answer:

Answer is A

Step-by-step explanation:

$m = y2 - y1 \div x2 - x1 \\ y2 = m(x2 - x1) + y1$

6 0

3 years ago

Nerissa has 5 pink bows, 1 blue bow, and 4 purple bows in a box. She will randomly choose 1 bow from the box. What is the probab

Ilya [14]

Answer:

4/10 or 40% chance

6 0

2 years ago

Read 2 more answers

What is the average rate of change between hour 15 and hour 30

adell [148]

Answer:

5 hours

Step-by-step explanation:

there is no picture so i'm gonna just sya 5 because 5 + 15 is 30 .

5 0

3 years ago

PLS HURRY GIVING BRAINLIEST

AlexFokin [52]

Answer:

150Ft^2

Step-by-step explanation:

The area of a parallelogram is A=BH where B is base length and H is height. I'm not sure why there is information about a triangular base, maybe an illustration would help. But with the information provided, the base times height is equal to 150 Ft^2. Check out the Kahn Academy video for a better explanation

5 0

2 years ago

Read 2 more answers

Scores on a test are normally distributed with a mean of 81.2 and a standard deviation of 3.6. What is the probability of a rand

Misha Larkins [42]

<u>Answer:</u>

The probability of a randomly selected student scoring in between 77.6 and 88.4 is 0.8185.

<u>Solution:</u>

Given, Scores on a test are normally distributed with a mean of 81.2

And a standard deviation of 3.6.

We have to find What is the probability of a randomly selected student scoring between 77.6 and 88.4?

For that we are going to subtract probability of getting more than 88.4 from probability of getting more than 77.6

Now probability of getting more than 88.4 = 1 - area of z – score of 88.4

$\mathrm{Now}, \mathrm{z}-\mathrm{score}=\frac{88.4-\mathrm{mean}}{\text {standard deviation}}=\frac{88.4-81.2}{3.6}=\frac{7.2}{3.6}=2$

So, probability of getting more than 88.4 = 1 – area of z- score(2)

= 1 – 0.9772 [using z table values]

= 0.0228.

Now probability of getting more than 77.6 = 1 - area of z – score of 77.6

$\mathrm{Now}, \mathrm{z}-\text { score }=\frac{77.6-\text { mean }}{\text { standard deviation }}=\frac{77.6-81.2}{3.6}=\frac{-3.6}{3.6}=-1$

So, probability of getting more than 77.6 = 1 – area of z- score(-1)

= 1 – 0.1587 [Using z table values]

= 0.8413

Now, probability of getting in between 77.6 and 88.4 = 0.8413 – 0.0228 = 0.8185

Hence, the probability of a randomly selected student getting in between 77.6 and 88.4 is 0.8185.

4 0

3 years ago

Can someone help me lol​

Can someone help me lol