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ololo11 [35]
2 years ago
14

Can someone help me lol​

Mathematics
1 answer:
Ivenika [448]2 years ago
4 0
Answer: 51
80+49=129
180-129= 51
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Which of the following expressions are equivalent to -45+12
meriva

Answer:

-45 + 12 is equal to -33

and <u>Choice A </u> is also equal to -33.

Step-by-step explanation:

7 0
2 years ago
Evaluate y/2x-z x=4y=3and z=2
Gwar [14]
First you plug in the missing values
y=3 x=4 z=2
3÷2×4-2
than you solve
the answer is 4
5 0
3 years ago
3x-y=1;d:{-3,-1,0,4}
Maslowich
First, rearrange the equation so that it is solving for y:
3x - y = 1
     +y   +y
3x = y + 1
-1         -1
3x - 1 = y
Now substitute the domain values you have listed into the 'x' of the equation to get the values for y.
For example:
3(-3) - 1 = y
-9 - 1 = y
y = -10
8 0
3 years ago
The following parts refer to the letters: LAMEFIREALARM. Recall that "word" means distinguishable letter arrangements. (a) How m
larisa86 [58]

Answer:

Step-by-step explanation:

The word "LAMEFIREALARM" word consists of

2L , 2M, 2E , 2R , 3A , F and I

no of words with the above letters such that M's are not together

=Total No of words- M's are together

Total no of words=\frac{13!}{4\times 2!\times 3!}=64,864,800

When M's are together . considering 2 M's as one

therefore there are \frac{12!}{3\times 2!\times 3!}=9,979,200

No of ways=\frac{13!}{4\times 2!\times 3!}-\frac{12!}{3\times 2!\times 3!}=54,885,600

(b)No of ways such that M's are separated by at least 2 letters

at least  2 letter means 2 letter, 3 letter ......11 letters

So we have to subtract no of ways where there are 1 letter in between M's from total no of ways where 2 M's are not next to each other

No of ways in which there is 1 letter between 2 M's

This can be done by considering 11 cases

In first case Place first M in Starting Position and 2 M on third place

Second case place First M in 2 nd Position and second M on 4 th place

Similarly For 11th case

Place first M in 11th place and second M on 13th place

Total ways

=\frac{11\times 11!}{3!\times 2!\times 2!\times 2!}

So , the total number of arrangements of the letters of the word LAMEFIREALARM where the two M's are separated by atleast two letters is

=\frac{13!}{4\times 2!\times 3!}-\frac{12!}{3\times 2!\times 3!}-\frac{11\times 11!}{3!\times 2!\times 2!\times 2!}

=45738000

7 0
3 years ago
SoMeonE plZ hAlp me lol
jeka94

C.√93


A=17

B=14

...........................

3 0
2 years ago
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