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2 years ago

Find the sizes of unknow angles of this triangle

Mathematics

1 answer:

Volgvan2 years ago

4 0

<h2><u>Answer:</u></h2>

To determine to measure of the unknown angle, be sure to use the total sum of 180°. If two angles are given, add them together and then subtract from 180°. If two angles are the same and unknown, subtract the known angle from 180° and then divide by 2.

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6 multiplication problems that ar involved in the solving of 325×89

gogolik [260]

325*89.1

Let's decompose this into:

325 = 300 + 25

89.1 = 80 + 9 + 0.1

Then we have the multiplication:

(300 + 25)*(80 + 9 + 0.1)

Let's distribute the multiplication:

300*80 + 300*9 + 300*0.1 + 25*80 + 25*9 + 25*0.1

So now we have 6 multiplications that are a lot easier to solve than the initial one that we had.

Then the list of six multiplications involved in solving this problem are:

300*80 = 24,400

300*9 = 2,700

300*0.1 = 30

25*80 = 2,000

25*9 = 225

25*0.1 = 2.5

Now we add all of those and get:

325*89.1 = 24,400 + 2,700 + 30 + 2,000 + 225 + 2.5 = 28,957.5

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3 years ago

The table shows the total distance that Myra runs over different time periods.

Oliga [24]

Answer:

its d

Step-by-step explanation:

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3 years ago

What is another way to name line l? need help asap

kkurt [141]

Answer:

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6 0

3 years ago

Read 2 more answers

HELP ASAP WILL MARK BRAINLIEST

DochEvi [55]

Answer:

EF , HG , Parallel

Step-by-step explanation:

Here we are given a translated quadrilateral EFGH from Quadrilateral ABCD.

Also given that AB was parallel to DC.

Now we have to fill in the certain blanks.

Here EF is parallel to AB , As EFGH is a translated image of ABCD. And EF and AB are the corresponding sides.

Also HG is parallel to DC, EFGH is a translated image of ABCD.

Also we are given that AB is parallel to DC. Hence we have following results.

AB║DC

AB║EF

Hence CD║EF

also

CD ║HG

CD║EF

Hence we can come to conclusion that

EF║HG

Hence our answer will be

corresponding segments EF and HG are parallel to each other.

3 0

3 years ago

30 POINTS!! ASAP! PLS SHOW WORK

sp2606 [1]

Answer:

QII

Step-by-step explanation:

We can use the acronym: ASTC or All Students Take Calculus.

The first letter of each word tells us details within a certain quadrant.

All trig functions in QI will be positive.

Only sine (and cosecant) will be positive in QII.

Only tangent (and cotangent) will be positive in QIII.

And only cosine (or secant) will be positive in QIV.

We know that tan(θ)<0. In other words, it's negative.

So, it our angle θ <em>cannot</em> be in QI or QIII.

We also know that cos(θ)<0.

So, this removes QIV, since in QIV, cosine is positive.

Therefore, the only choices that remains is QII.

In QII, sine is positive, tangent is negative, and cosine is negative.

This fits all our conditions, so θ is in QII.

And we're done!

3 0

3 years ago

Find the sizes of unknow angles of this triangle​

Find the sizes of unknow angles of this triangle