v₀ = initial velocity of the freight train while it approach a road crossing = 16 km/h = 16 (5/18) m/s = 4.44 m/s
v = final velocity of the freight train after it crosses a road crossing = 65 km/h = 65 x 5/18 m/s = 18.06 m/s
t = time to do so = 10 min = 10 x 60 sec = 600 sec
acceleration is given as
a = (v - v₀ )/t
a = (18.06 - 4.44)/(600)
a = 0.023 m/s²
a = 294
Answer:
A
Step-by-step explanation:
well some people like to go on a budget and others prefer not to because they rather spend their money money on wants rather than needs so I really hope this helps.
<em>Your answer will be, </em><em>"6p - 8"</em>
Thanks,
<em>Deku ❤</em>
It's the value of 
when 
:
When , the derivative/slope is 2, so the answer is C.
Answer:
Step-by-step explanation: just search it up
