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Svetradugi [14.3K]
3 years ago
8

Please help! What is the answer to this question?​

Mathematics
1 answer:
valentinak56 [21]3 years ago
5 0

Answer:

b. 80

Step-by-step explanation:

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He graph of the function f(x) = –(x + 6)(x + 2) is shown below.
Molodets [167]

The domain of the function is all real numbers, the range of a function is y ≤ 4

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have a function:

f(x) = –(x + 6)(x + 2)

If we plot this function on the coordinate plane, we will see it is a graph of a quadratic function.

Here the no other details are given.

But we can say:

  • The domain of the function is all real numbers.
  • The range of a function is y ≤ 4
  • The x-axis intercept will be at (-6, 0) and (-2, 0).

Thus, the domain of the function is all real numbers, the range of a function is y ≤ 4

Learn more about the function here:

brainly.com/question/5245372

#SPJ1

6 0
2 years ago
What is equivalent to 9^x=27
erma4kov [3.2K]
If you meant to solve for x...

9^x=27 \\&#10;(3^2)^x=3^3\\&#10;3^{2x}=3^3\\&#10;2x=3\\&#10;x=\dfrac{3}{2}
8 0
3 years ago
There are 21 bags of pears on a market stall.
geniusboy [140]

Answer:

13 pears in the 21st bag

Step-by-step explanation:

mean = total number of pears/total number of bags

8 = x/21

x = 168

number of pears in 20 bags = (6 x 2) + (7 x 6) + (8 x 9) + (9 x 1) + (10 x 2)

= 155

number of pears in the 21st bag = 168 - 155

= 13

4 0
3 years ago
D.
Inga [223]
I don’t know the answer to this question
7 0
2 years ago
A homeowner has an octagonal gazebo inside a circular area. Each vertex of the gazebo lies on the circumference of the circular
Tcecarenko [31]

If we draw the diagonals of the octagonal gazebo, the 4 diagonals divide the octagon into 8 triangles.

Note that each triangle is an isosceles triangle whose equal sides are x, the radius of the circle.

The top angle of each triangle is obtained by dividing the full angle by 8.

So, each top angle = \frac{360}{8}

= 45°

Now, in fig., consider one of the triangles Δ OAB. Draw an altitude OC from O to the opposite side AB.

This altitude OC bisects the top angle 45°.

Therefore, ∠ AOC = 22.5°.

Now, in Δ AOC,

sin 22.5=\frac{AC}{OA}

=\frac{AC}{x}

So, AC = x sin 22.5°

Note that, AB = 2 AC.

Therefore, AB = 2x sin 22.5°.

Also, cos 22.5=\frac{OC}{OA}

=\frac{OC}{x}

So, OC = x cos 22.5°.

Area of Δ AOB = \frac{1}{2}(AB)(OC)

= \frac{1}{2} × (2x sin 22.5°) × (x cos 22.5°)

= \frac{1}{2} x^{2} (2 sin 22.5° cos 22.5°)

= \frac{1}{2} x^{2} sin 45°

= x^{2} / 2\sqrt{2}

Area of the octagonal gazebo = 8 × one triangular area

= 8 × (x^{2} / 2\sqrt{2})

=2\sqrt{2} x^{2}

=2.828x^{2}

Area required for mulch = circular area - area of the gazebo

=3.14x^{2} -2.828x^{2}

=0.312x^{2}

Now, cost per unit area = $1.50.

Hence, total cost g(m) = area × cost per unit area

Total cost g(m) = 0.312x^{2} × 1.5

=0.468x^{2}

Hence, total cost g(m) = 0.468x^{2}.

4 0
3 years ago
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