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sweet-ann [11.9K]
2 years ago
7

HELP PLSS ILL GIVE BRAINLESS

Mathematics
2 answers:
Ivan2 years ago
8 0
Yellow is the answer
hram777 [196]2 years ago
7 0

Answer:

Green = 26.86 or 26.855

Yellow = 50.28 or 50.275

Blue = 36.85

Step-by-step explanation:

Use the formulas for perimeter

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

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Frank’s quarter grades are 82.5, 94.7, and 87.9. What grade, rounded to the nearest percent, will Frank have to earn in the last
yanalaym [24]
He would have to atleast get a A:89% because 82.5+94.7+87.9+89=354.1/4=88.525=89% (rounded to the nearest percent) to find this just take 82.5+94.7+87.9+x=xx/4=atleast 89% mainly it just is guess and check to find this. Hope this helps!=)
5 0
2 years ago
WRITE DOWN THE FALUE OF 7
Maru [420]

Answer:

(I need to know where the seven is located/placed.) Please give a clear answer or attach a photo next time so everybody who sees your question will understand.

Step-by-step explanation:

Comparing the numbers 700, 70, and 7; the digit "7" has a different value depending on its place within the number.

7 - ones place

70 - tens place

700 - hundreds place

The place value of the 7 determines the value it holds for the number. As the place moves to the left, the value of the number becomes greater by 10 times

8 0
3 years ago
Read 2 more answers
Use the information provided to determine a 95% confidence interval for the population variance. A researcher was interested in
Leno4ka [110]

Answer:

The 95% confidence interval for the population variance is (8.80, 32.45).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the population variance is given as follows:

\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}

It is provided that:

<em>n</em> = 20

<em>s</em> = 3.9

Confidence level = 95%

⇒ <em>α</em> = 0.05

Compute the critical values of Chi-square:

\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.05/2, (20-1)}=\chi^{2}_{0.025,19}=32.852\\\\\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.05/2, (20-1)}=\chi^{2}_{0.975,19}=8.907

*Use a Chi-square table.

Compute the 95% confidence interval for the population variance as follows:

\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}

\frac{(20-1)\cdot (3.9)^{2}}{32.852}\leq \sigma^{2}\leq \frac{(20-1)\cdot (3.9)^{2}}{8.907}\\\\8.7967\leq \sigma^{2}\leq 32.4453\\\\8.80\leq \sigma^{2}\leq 32.45

Thus, the 95% confidence interval for the population variance is (8.80, 32.45).

4 0
2 years ago
HELP ME PLEASE: I WILL GIVE BRAINLIEST AND IT IS 20 POINTS
Anastaziya [24]

Answer:

0

Step-by-step explanation:

any log with a base of one and it becomes logv5 (1) after logv5(logV3 (3) because log3(3) equal one so then logv5 (1) is 0

8 0
2 years ago
Ariana bought 5 dozen pears at $36 per dozen . She discovered that 7 were rotten and she sold the rest at $4.50 each . Calculate
GrogVix [38]

Step-by-step explanation:

1 dozen = 12 pears

12 pears = $36

1 pear = 36/12 = $3

Total Cost of Pears = No. of pears x price of 1 pear

= (5x12) x 3

= 60 x 3

= $180

Sale of Pears = Price per pear x (Total Pears bought - Rotten Pears)

= $4.50 x (5x12-7)

= $4.50 x 53

= $238.50

Profit/Loss = Sale of Pears - Total Cost of Pears

= $238.50 - $180

= $58.50

Ariana made a profit of $58.50.

5 0
3 years ago
Read 2 more answers
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