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kaheart [24]
3 years ago
15

The graph of which of the following equations contains the points (2,3) and (3,2)

Mathematics
1 answer:
Crazy boy [7]3 years ago
5 0

Answer:

y = 5 - x

Step-by-step explanation:

The graph of the equation that will contain the points (2, 3) and (3, 2) is the graph that has a slope value that is equivalent to the slope value of the line running through the two points.

Slope of the line running through (2, 3) and (3, 2):

slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{2 - 3}{3 - 2} = \frac{-1}{1} = -1.

Slope (m) = -1.

The equation, y = 5 - x , is given in the slope-intercept form, which means it has a slope value of -1. I.e. the term "-x" is equivalent to -1x. So therefore, the graph of the equation that contains the points (2, 3) and (3, 2) is y = 5 - x.

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Help please this is for inequality math!! n + 7 < - 3
stealth61 [152]

Answer:

n < -10

Step-by-step explanation:

n+7 < -3

subtract 7 from both sides

n+7-7 < -3-7

n < -10

4 0
3 years ago
If the function f is given by f(x)= 4x -3, find the value of f(2+h)
Travka [436]
  • f(x)=4x-3

\\ \sf\longmapsto f(2+h)

\\ \sf\longmapsto 4(2+h)-3

\\ \sf\longmapsto 4h+8-3

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6 0
3 years ago
A discuss moves from P1 (4,8) to P2 (15,17). What is the lincar displacement in the horizontal and vertical directions? What is
Yakvenalex [24]

Answer:

The horizontal displacement is 11 units, the vertical displacement is 9 units, and the projection angle is 39.3 degrees.

Step-by-step explanation:

We can start using the definition of displacement in one dimension between any 2 points which is the difference between them, so we have

\Delta s = s_2-s_1

And apply it to get the horizontal and vertical displacements.

Once we have found them, we can use trigonometric functions to find the projection angle with respect the horizontal.

Linear displacements.

Using the definition of displacement, we can write the horizontal displacement as

\Delta x = x_2-x_1

So we can use the given points P1:(x_1,y_2)  \text{  and  } P_2: (x_2,y_2) on the displacement formula

\Delta x = 15-4\\\Delta x = 11

In the same manner we can look at the y components of those points to find the vertical displacement

\Delta y = 17-8\\\Delta y =9

Thus the horizontal displacement is 11 units and the vertical displacement is 9 units.

Projection angle.

The projection angle with respect the horizontal is the angle that is made between the line that connects the points P1 and P2 and the horizontal, so we can use the linear displacements previously found to write

\tan(\theta) = \cfrac{\Delta y}{\Delta x}

Solving for the angle we get

\theta = \tan^{-1}\left(\cfrac{\Delta y}{\Delta x}\right)

Replacing values

\theta = \tan^{-1}\left(\cfrac{9}{11}\right)

Which give us

\theta = 39.3^\circ

So the projection angle is 39.3 degrees.

7 0
3 years ago
Graph the following inequality :<br> - 2y z x + 6
saul85 [17]

Answer: 2(-2x+3)

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
How do you simply 2x+8=-6
photoshop1234 [79]
To simplify <span>2x + 8 = -6, the easiest way is to manipulate the equation one step at a time:

</span>2x + 8 = <span>-6
</span>2x = <span>-14             (subtract 8 from both sides)
</span>x = -7                 (divide both sides by 2)


3 0
3 years ago
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