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3 years ago

4) You randomly select one card from a 52-card deck. Find the probability of selecting the 6 of hearts or the ace of diamonds.

Mathematics

2 answers:

MakcuM [25]3 years ago

8 0

Answer:

1/26

Step-by-step explanation:

There is only one 6 of hearts and only one ace of diamonds.

The probability of selecting the 6 of hearts is thus 1/52, and that of selecting the ace of diamonds is also 1/52.

The probability of selecting the 6 of hearts or the ace of diamonds is the SUM of these two results: 1/52 + 1/52 = 2/52 = 1/26.

Bumek [7]3 years ago

6 0

1/26
I hope this can help you!!!

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Answer:

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Step-by-step explanation:

Given:

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$56=-16t^2+120t$

Rewriting the above equation into a standard quadratic equation and solving for 't', we get:

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Using quadratic formula to solve for 't', we get:

$t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t=\frac{-(-15)\pm \sqrt{(-15)^2-4(2)(7)}}{2(2)}\\\\t=\frac{15\pm \sqrt{225-56}}{4}\\\\t=\frac{15\pm\sqrt{169}}{4}\\\\t=\frac{15\pm 13}{4}\\\\t=\frac{15-13}{4}\ or\ t=\frac{15+13}{4}\\\\t=\frac{2}{4}\ or\ t=\frac{28}{4}\\\\t=0.5\ s\ or\ t=7\ s$

Therefore, the debris will reach a height of 56 ft twice.

When time $t=0.5\ s$ during the upward journey, the debris is at height of 56 ft.

Again after reaching maximum height, the debris falls back and at $t=7\ s$ , the height is 56 ft.

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<h3>Answer:</h3>

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4) You randomly select one card from a​ 52-card deck. Find the probability of selecting the 6 of hearts or the ace of diamonds.

4) You randomly select one card from a 52-card deck. Find the probability of selecting the 6 of hearts or the ace of diamonds.