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elena55 [62]
3 years ago
5

What is the range 2 7 7 5 3 4 3

Mathematics
1 answer:
ELEN [110]3 years ago
7 0

Answer:

The range is 5

Step-by-step explanation:

7-2=5

You might be interested in
The number 9.37 rounded to the nearest tenth is 9.4 Is this correct?y or y not
PSYCHO15rus [73]
Yes, this is correct. The tenths place is the first number to the right of the decimal. There is a 3 in that spot
To find if it rounds up or down, follow this rule.
Less than 5 round down and greater than 5 round up.
For this you look to the number next to it which is 7.
It rounds up so it is 9.4
8 0
3 years ago
Read 2 more answers
if alpha and beta are the zeroes of the polynomial f(x) = 6x² + x - 2, find the value of 1/alpha + 1/beta - alphabeta​
finlep [7]

Answer:

let alpha be x and beta be y

Step-by-step explanation:

x+y= -b/a

x+y=-1/6

and xy= c/a

xy= -1/3

according to question

1/x+1/y -xy =(x+y)/xy-xy

(-1/6)/(-1/3)-(-1/3)

1/2+1/3

the answer is 5/6

7 0
3 years ago
We are driving to Las Vegas. The sign says that it is one hundred forty-five miles to Las Vegas.
nata0808 [166]

Answer:

233.35488 km (Rounded to 233 km)

Step-by-step explanation:

If you convert miles to kilometers then you would use this conversion factor:

1 mile = 1.609344 km (or 1.61 km)

so in this case,

145 mile = 1.609344 km x 145

145 mile = 233.35488 km

I could also round it to 233 km.

Since your on a trip... i hope u enjoy ur journey to Las Vegas!

5 0
1 year ago
(5×10^-5) +(2.46×10^-3)​
maxonik [38]
My work to your question

5 0
3 years ago
In general, the probability that a blood donor has Type A blood is 0.40.Consider 8 randomly chosen blood donors, what is the pro
postnew [5]

Answer:

The probability that more than half of them have Type A blood in the sample of 8 randomly chosen donors is P(X>4)=0.1738.

Step-by-step explanation:

This can be modeled as a binomial random variable with n=8 and p=0.4.

The probability that k individuals in the sample have Type A blood can be calculated as:

P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{8}{k} 0.4^{k} 0.6^{8-k}\\\\\\

Then, we can calculate the probability that more than 8/2=4 have Type A blood as:

P(X>4)=P(X=5)+P(X=6)+P(X=7)+P(X=8)\\\\\\P(x=5) = \dbinom{8}{5} p^{5}(1-p)^{3}=56*0.0102*0.216=0.1239\\\\\\P(x=6) = \dbinom{8}{6} p^{6}(1-p)^{2}=28*0.0041*0.36=0.0413\\\\\\P(x=7) = \dbinom{8}{7} p^{7}(1-p)^{1}=8*0.0016*0.6=0.0079\\\\\\P(x=8) = \dbinom{8}{8} p^{8}(1-p)^{0}=1*0.0007*1=0.0007\\\\\\\\P(X>4)=0.1239+0.0413+0.0079+0.0007=0.1738

3 0
3 years ago
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