If the reserve rate is 7% and a bank receives a deposit of $9000, how much of the $9000 is the bank free to lend?

Ian puts 300.00 into an account to use for school expenses the account earns 6%interest compounded annually how much will be in

romanna [79]

This problem is about componded interest. The formula for compounded interest is:

$\begin{gathered} \text{Amount}=\text{Initial}\cdot(1+r)^t \\ \text{Where,} \\ \text{Amount is the total acumulative at time t.} \\ \text{Initial is the initial amount, at t=0} \\ r\text{ is the interest in decimal number.} \\ t\text{ is the time accordingly the interest, in this case is in years.} \end{gathered}$

In this case, Initial = 300, r = 0.06 and t=10 so the total amount in the account after 10 years is:

$\begin{gathered} \text{Amount}=300\cdot(1+0.06)^{10} \\ \text{Amount}=300\cdot1.06^{10} \\ \text{Amount}=300\cdot1.79085 \\ \text{Amount}=537.255 \end{gathered}$

The amount after 10 years is 573.26.

4 0

1 year ago

The jars of peanut butter that I buy cost $7.20 each and normally contain 500 grams. At present, however, each jar contains an e

Alex_Xolod [135]

Answer:

$0.54

Step-by-step explanation:

Given:

The jars of peanut butter that I buy cost $7.20 each and normally contain 500 grams.

At present, however, each jar contains an extra 20% free.

And additionally, the supermarket has a "buy 3 jars get another one free''.

Question asked:

By how much is the cost per 100 grams of peanut butter less than it normally is if I take full advantage of the supermarket's offer today?

Solution:

Cost of a jars of peanut = $7.20

Normally, weight of peanut butter in one packet = 500 gram

At supermarket offer, each jar contains an extra 20% free, means a packet of peanut butter contains = 500 + 20% of 500 $=500+500\times \frac{20}{100} =500+100=600\ gram$

And extra benefit = buy 3 jars get another one free, means we will get 4 jars by just giving price of only 3 jars.

That means, total weight of peanut butter you are getting by giving 3 packet's price = Each jar weigh $\times$ number of jars

= 600 $\times$ 4 = 2400 gram

Cost of each packet will be same as previously as during the offer; $7.20

Cost of 3 packet's peanut (2400 gram) = $7.20\times3=\$21.6$

Now, we will calculate cost per 100 grams of peanut butter :

During offer:

Cost of 2400 grams of peanut butter = $21.6

Cost of 1 gram of peanut butter = $\frac{21.6}{2400}$

Cost of 100 gram of peanut butter = $\frac{21.6}{2400}\times100=\frac{2160}{2400} =\$0.9$

Normal day:

Cost of 500 grams of peanut butter = $7.20

Cost of 1 gram of peanut butter = $\frac{7.20}{500}$

Cost of 100 gram of peanut butter = $\frac{7.20}{500}\times100=\frac{720}{500} =\$1.44$

We found that cost of 100 gram of peanut butter in normal day is $1.44 while cost of 100 gram of peanut butter during offer is $0.9 means cost per 100 gram during offer is ($1.44 - $0.9 = )$0.54 less than cost during normal day.

Conclusion:

Therefore, cost per 100 grams of peanut butter is $0.54 less than it is normally if you take full advantage of the supermarket's offer today.

7 0

3 years ago

Simplify 4(b-6)+19 ?

Digiron [165]

Answer:

4b -5

Step-by-step explanation:

Perform the indicated multiplication first: 4b - 24 + 19. Next, combine like terms, obtaining 4b -5 (answer)

4 0

3 years ago

Ms.Erma's oatmeal recipes calls for 2/5 of a cup of raisins.How many batches of cookies can she make if she has 4/5 cup of raisi

Tanya [424]

2 batches because 4/2 =2

6 0

3 years ago

Given:• PQRS is a rectangle.• mZ1 = 50°Р21SRWhat is mZ2?130°85°70°65°

Over [174]

To answer this question, we need to recall that: "the diagonals of a rectangle bisect each other"

Thus, if we assign the point of intersection of the two diagonals in the rectangle as point O, we can say that the triangle OQR is an "isosceles triangle". Note that this is because the lengths OR and OQ are equal since we know that: "the diagonals of a rectangle bisect each other". See the below diagram for clarity.

Now, we have to recall that:

- the base angles of any isosceles triangle are equal. This is a fact, and this means that the angles

- also the sum of all the angles in any triangle is 180 degrees

Now, considering the isosceles triangle OQR, we have that:

$\angle OQR+\angle ORQ+\angle ROQ=180^o$

Now, since the figure already shows that angle $m\angle2+\angle ORQ+50^o=180^o$ Now, since we have established that the base angles $m\angle2+m\angle2+50^o=180^o$ we can now solve the above equation for m<2 as follows:

$\begin{gathered} m\angle2+m\angle2+50^o=180^o \\ \Rightarrow2m\angle2+50^o=180^o \\ \Rightarrow2m\angle2=180^o-50^o \\ \Rightarrow2m\angle2=130^o \\ \Rightarrow m\angle2=\frac{130^o}{2}=65^o \end{gathered}$

Therefore, the correct answer is: option D

7 0

1 year ago