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3 years ago

Can someone help me with these

Mathematics

1 answer:

bazaltina [42]3 years ago

7 0

Answer:

2 - 3 x (N)= N + 10 (n=6)

Step-by-step explanation:

These equations are the same basically. 3 times a number -2 is the equivalent of a number + 10. If the number was 6 then it would work like this. 3 times 6 is 18, then subtracted by 2 is 16, which is equal to 6+10 (16). Hope you understand!

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Answer:

50 in total, 45 were eaten

Step-by-step explanation:

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

What is StartFraction 7 Over 9 EndFraction divided by one-third?

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3 years ago

Read 2 more answers

The researcher has limited resources. He sends 9 emails from a Latino name, and 14 emails from a non-Latino name. For the Latino

deff fn [24]

Answer: 38.41 minutes

Step-by-step explanation:

The standard error for the difference in means is given by :-

$SE.=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma^2_2}{n_2}}$

where , $\sigma_1$ = Standard deviation for sample 1.

$n_1$ = Size of sample 1.

$\sigma_2$ = Standard deviation for sample 2.

$n_2$ = Size of sample 2.

Let the sample of Latino name is first and non -Latino is second.

As per given , we have

$\sigma_1=82$

$n_1=9$

$\sigma_2=101$

$n_2=14$

The standard error for the difference in means will be :

$SE.=\sqrt{\dfrac{(82)^2}{9}+\dfrac{(101)^2}{14}}$

$SE.=\sqrt{\dfrac{6724}{9}+\dfrac{10201}{14}}$

$SE.=\sqrt{747.111111111+728.642857143}$

$SE.=\sqrt{1475.75396825}=38.4155433158\approx38.41$

Hence, the standard error for the difference in means =38.41 minutes

3 0

3 years ago

pH measurements of a chemical solutions have mean 6.8 with standard deviation 0.02. Assuming all pH measurements of this solutio

aalyn [17]

Answer: 2.14 %

Step-by-step explanation:

Given : pH measurements of a chemical solutions have

Mean : $\mu=6.8$

Standard deviation : $\sigma=0.02$

Let X be the pH reading of a randomly selected customer chemical solution.

We assume pH measurements of this solution have a nearly symmetric/bell-curve distribution (i.e. normal distribution).

The z-score for the normal distribution is given by :-

$z=\dfrac{x-\mu}{\sigma}$

For x = 6.74

$z=\dfrac{6.74-6.8}{0.02}=-3$

For x = 6.76

$z=\dfrac{6.76-6.8}{0.02}=-2$

The p-value = $P(6.74$

$P(z$

In percent, $0.0214\times=2.14\%$

Hence, the percent of pH measurements reading below 6.74 OR above 6.76 = 2.14%

6 0

3 years ago