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2 years ago

Select all of the prime numbers from the list that can divide the number 10 exactly.

Mathematics

1 answer:

spin [16.1K]2 years ago

8 0

Answer:

2 and 5

Step-by-step explanation:

2×5 = 10 or visa versa

10 ÷5=2

10 ÷2 =5

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How to find a outliers<br>

Liula [17]

Answer: It is something that is really far away from the rest of your data

Step-by-step explanation: for example find the outlier: -1 2 3 7 10 20 the outlier is 20

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3 years ago

2x - 3 > 15 or 3 + 7x < 17

Viktor [21]

Answer:

2x-3>15 and 3-7x>17 =

3-7x>17

-7x>14

x<-2

Step-by-step explanation:

Sorry this is not a proper equation. I think you meant this equation.

2x-3>15 and 3-7x>17

for this equation the answer is

3-7x>17

-7x>14

x<-2

6 0

2 years ago

What operation would you use to solve: x+7=10

djyliett [7]

Answer:

x=3

Step-by-step explanation:

x+7=10

x+7-7=10-7

x=3

5 0

2 years ago

Read 2 more answers

Find three consecutive odd integers such that 10 times the first, plus 10 times the second, equals 10 more than 10 times the thi

SIZIF [17.4K]

Answer:

Step-by-step explanation:

If x is the third number, then x−1 and x−2 are the second and first numbers.

10(x−2) + 10(x−1) = 10 + 10x

x − 2 + x − 1 = 1 + x

2x − 3 = 1 + x

x = 4

8 0

3 years ago

Suppose a simple random sample of size nequals36 is obtained from a population with mu equals 74 and sigma equals 6. (a) Descri

OlgaM077 [116]

Part a)

The simple random sample of size n=36 is obtained from a population with

$\mu = 74$

and

$\sigma = 6$

The sampling distribution of the sample means has a mean that is equal to mean of the population the sample has been drawn from.

Therefore the sampling distribution has a mean of

$\mu = 74$

The standard error of the means becomes the standard deviation of the sampling distribution.

$\sigma_ { \bar X } = \frac{ \sigma}{ \sqrt{n} } \\ \sigma_ { \bar X } = \frac{ 6}{ \sqrt{36} } = 1$

Part b) We want to find

$P(\bar X \:>\:75.9)$

We need to convert to z-score.

$P(\bar X \:>\:75.9) = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: 1.9) \\ = 0.0287$

Part c)

We want to find

$P(\bar X \: < \:71.95)$

We convert to z-score and use the normal distribution table to find the corresponding area.

$P(\bar X \: < \:71.95) = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: - 2.05) \\ = 0.0202$

Part d)

We want to find :

$P(73\:$

We convert to z-scores and again use the standard normal distribution table.

$P( \frac{73 - 74}{1} \:< \: z$

5 0

2 years ago