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Amiraneli [1.4K]
4 years ago
5

Find the surface area

Mathematics
1 answer:
uysha [10]4 years ago
7 0
If you notice, the figure has two hexagonal faces and 6 rectangles.

now the rectangles are just 4x9 each, so their area is just 6(4*9) for all 6.

the hexagons has a distance from the center perpendicular to a side of 7.8, namely the apothem is 7.8, and since each side is 9 km long, the perimeter is 9+9+9+9+9+9.

since the area of a regular polygon is (1/2)(apothem)(perimeter), we can simply get the area of those two hexagons and the area of the rectangles, sum them up, and that's the surface area of the hexagonal prism.

\bf \stackrel{\textit{6 rectangles}}{6(4\cdot 9)}~~~~+~~~~\stackrel{\textit{2 hexagons}}{2\left[ \cfrac{1}{2}(7.8)(54) \right]}
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You roll two six-sided fair dice. a. Let A be the event that the first die is odd and the second is a 4, 5, or 6. P(A) =? Round
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a. \dfrac{1}{4}

b. \dfrac{1}{12}

c. Not mutually exclusive.

d. Not independent events

Step-by-step explanation:

a. When two six-sided fair dice are rolled one time,

Total possible outcomes, n(S) = 6 × 6 = 36,

If A be the event that the first die is odd and the second is a 4, 5, or 6

Then, A = {(1, 4), (3, 4), (5, 4), (1, 5), (3, 5), (5, 5), (1, 6), (3, 6), (5, 6)}

i.e. n(A) = 9,

\because \text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}

Thus, the probability of event A,

P(A) = \frac{n(A)}{n(S)}=\frac{9}{36}=\frac{1}{4}

b. if B be the event that the sum of the two dice is 10,

Then B = {(4, 6), (5, 5), (6, 4)}

i.e. n(B) = 3,

Thus, the probability of event B,

P(B) = \frac{n(B)}{n(S)}=\frac{3}{36}=\frac{1}{12}

c. Two event are called mutually exclusive events,

If they are disjoint,

i.e. A and B are mutually exclusive,

If A ∩ B = ∅

∵ {(1, 4), (3, 4), (5, 4), (1, 5), (3, 5), (5, 5), (1, 6), (3, 6), (5, 6)} ∩ {(4, 6), (5, 5), (6, 4)}

= {(5, 5)} ≠ ∅

So, they are not mutually exclusive events.

d. Two events are called independent if the occurrence of one event does not affect the occurrence of other event.

Also, A and B are independent events,

If P(A ∩ B) = P(A) × P(B)

n(A∩ B) = 1,

\implies P(A\cap B)=\frac{n(A\cap B)}{n(S)}=\frac{1}{36}

∵ \frac{1}{4}\times \frac{1}{12}=\frac{1}{48}\neq \frac{1}{36}

Hence, they are not independent events.

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