PLZ HURRY IM I A RUSH THIS FOR 40 POINTS!!
2 answers:
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Answer:
C
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m =
with (x₁, y₁ ) = (- 8, - 42 ) and (x₂, y₂ ) = (- 3, - 17 ) ← 2 ordered pairs from the table
m = =
=
= 5
The line crosses the y- intercept at (0, - 2 ) , then
y = 5x - 2 → C
I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
SEE ATTACHED IMAGE.
Part A:
The differential equation is:
y '= 0.08y
The initial condition is:
P (0) = 500
Part B:
The formula for this case is:
P (t) = 500exp (0.08 * t)
Part C:
After five days we have to evaluate t = 5 in the equation.
We have then:
P (5) = 500 * exp (0.08 * 5)
P (5) = 745.9123488
Rounding:
P (5) = 746
SEE ATTACHED IMAGE.
Part A:
The differential equation is:
y '= 0.08y
The initial condition is:
P (0) = 500
Part B:
The formula for this case is:
P (t) = 500exp (0.08 * t)
Part C:
After five days we have to evaluate t = 5 in the equation.
We have then:
P (5) = 500 * exp (0.08 * 5)
P (5) = 745.9123488
Rounding:
P (5) = 746