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3 years ago

I need help with this one...

1 answer:

4 0

Pool A is 61.3 meters.
Pool B is 75.5 meters.

Explanation:
To find the circumstance, the equation is c=2(pi)(r).
So for pool A 2•3.14•32=201 Ft. but then you times 201 by .305 and you get 61.3 meters
Since pool b doesn’t give you a radius, you’ll have to find it. Which a diameter is just half a circle and the radius is the full so you times the diameter by two to find the radius. So the radius is 39.4. So for pool B it’s 2•3.14•39.4=247ft which times by .305 and you get 75.5.

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Help would be more then appreciated

BartSMP [9]

Answer:

Step-by-step explanation:

8 0

3 years ago

Help me please thanks:)))

yaroslaw [1]

125 = 5 * 5 * 5 = 5³

90 = 2 * 3 * 3 * 5 = 2 * 3² * 5

92 = 2 * 2 * 23 = 2² * 23

3 0

4 years ago

The scatterplot below shows the number of hours that some high school students spend on working and on video games.

sukhopar [10]

As the number of hours spent working increases, the amount of time spent on video games decreases.

Going from left to right, we see that the points are moving down. This means that the hours working are going up and the video game hours are going down.

7 0

4 years ago

Read 2 more answers

Suppose you want to eat lunch at a popular restaurant. The restaurant does not take reservations, so there is usually a waiting

grin007 [14]

Answer:

a) $z_1 =\frac{20-19}{4} =0.25$

$z_2 =\frac{15-19}{4} =-1$

And we can use the complement rule and we got:

$P(z>0.25)=1-P(z$

$P(z>-1)=1-P(z$

And replacing we got:

$P(X >20| X>15)= \frac{0.401}{0.841}= 0.477$

b) $z_1 =\frac{20-19}{4} =0.25$

$z_2 =\frac{18-19}{4} =-0.25$

And we can use the complement rule and we got:

$P(z>0.25)=1-P(z$

$P(z>-0.25)=1-P(z$

And replacing we got:

$P(X >20| X>18)= \frac{0.401}{0.599}= 0.669$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the length of time waiting to be seated of a population, and for this case we know the distribution for X is given by:

$X \sim N(19,4.0)$

Where $\mu=19$ and $\sigma=4.0$

Part a

For this cae we want to find this probability:

$P(X >20| X>15)$

And if we use the conditional probability formula we got:

$P(X >20| X>15)= \frac{P(X >20 \cap X>15)}{P(X>15)}=\frac{P(X>20)}{P(X>15)}$

We can solve the problem using the z score formula given by:

$z = \frac{x-\mu}{\sigma}$

$z_1 =\frac{20-19}{4} =0.25$

$z_2 =\frac{15-19}{4} =-1$

And we can use the complement rule and we got:

$P(z>0.25)=1-P(z$

$P(z>-1)=1-P(z$

And replacing we got:

$P(X >20| X>15)= \frac{0.401}{0.841}= 0.477$

Part b

$P(X >20| X>18)= \frac{P(X >20 \cap X>18)}{P(X>18)}=\frac{P(X>20)}{P(X>18)}$

We can solve the problem using the z score formula given by:

$z = \frac{x-\mu}{\sigma}$

$z_1 =\frac{20-19}{4} =0.25$

$z_2 =\frac{18-19}{4} =-0.25$

And we can use the complement rule and we got:

$P(z>0.25)=1-P(z$

$P(z>-0.25)=1-P(z$

And replacing we got:

$P(X >20| X>18)= \frac{0.401}{0.599}= 0.669$

5 0

4 years ago

A bathroom hac a length of 7 feet and a total area of 70 ft*2. What is the width of the bathroom?

deff fn [24]

Answer:

The width of the bathroom is 10ft.

Step-by-step explanation:

To find the area of a rectangle, we use the formula

area = width x length

So we know that length is equal to 7 ft, and we also know the total area which is 70 sq.ft.

70 = ? x 7

multiplication and division are inverse operations, so we will divide instead

70 divided by 7 = 10

And we are done!!

hope this helps you, feel free to leave any questions in the comments!! :)

3 0

3 years ago