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saul85 [17]
3 years ago
15

HELPP ITS DUE IN 10 MINUTES!!!!!

Mathematics
1 answer:
Degger [83]3 years ago
5 0

Answer:

a is less than or equal to 35 since 35 is the highest value that can be gotten

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What is the reason: if a+c=b+c then a=b
Tomtit [17]

Step-by-step explanation:

Example 1:

a+c=b+c then a=b

First let the value of a and b be different (not equal)

a=5

b=7

c=10

a+c=b+c

5+10=7+10

15≠17

Example 2:

Let the value a and b be equal (the same)

a=5

b=5

c=10

a+c=b+c

5+10=5+10

15=15

So when,

a+c and b+c is equal, a and b are <u>always</u><u> </u> equal.

Hope this helps ;) ❤❤❤

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3 years ago
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How many different ways can the front row seats be filled with 20 students if the classroom has 4 rows of seats? 1,860,480 116,2
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1860480 ways the front row seats can be filled
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4 years ago
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What are the domain and range and asympote of h(x)=6^x -4?
jeka94

Answer:

Domain: (-oo, oo)

Range: (-4,oo)

Horizontal asymptote: y=-4

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4 years ago
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What if the simplest form of the radical expression?
patriot [66]

Answer:

\large\boxed{\dfrac{\sqrt2+\sqrt5}{\sqrt2-\sqrt5}=-\dfrac{7+2\sqrt{10}}{3}}

Step-by-step explanation:

\text{Use}\ (a-b)(a+b)=a^2-b^2\ \text{and}\ (a+b)^2=a^2+2ab+b^2\\\\\\\dfrac{\sqrt2+\sqrt5}{\sqrt2-\sqrt5}=\dfrac{\sqrt2+\sqrt5}{\sqrt2-\sqrt5}\cdot\dfrac{\sqrt2+\sqrt5}{\sqrt2+\sqrt5}=\dfrac{(\sqrt2+\sqrt5)^2}{(\sqrt2)^2-(\sqrt5)^2}\\\\=\dfrac{(\sqrt2)^2+2(\sqrt2)(\sqrt5)+(\sqrt5)^2}{2-5}=\dfrac{2+2\sqrt{(2)(5)}+5}{-3}\\\\=-\dfrac{7+2\sqrt{10}}{3}

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4 years ago
PLEASE HELP IM BEGGING YOU!!<br> FIND THE VALUE OF X
Akimi4 [234]
X = 18.8 bc that’s the only thing that makes sense and us lazy people don’t need to work things out
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