X+5=18
first get rid of the 5
so X+5-5=18-5
which makes X=13
if any questions please ask
Here we must see in how many different ways we can select 2 students from the 3 clubs, such that the students <em>do not belong to the same club. </em>We will see that there are 110 different ways in which 2 students from different clubs can be selected.
So there are 3 clubs:
- Club A, with 10 students.
- Club B, with 4 students.
- Club C, with 5 students.
The possible combinations of 2 students from different clubs are
- Club A with club B
- Club A with club C
- Club B with club C.
The number of combinations for each of these is given by the product between the number of students in the club, so we get:
- Club A with club B: 10*4 = 40
- Club A with club C: 10*5 = 50
- Club B with club C. 4*5 = 20
For a total of 40 + 50 + 20 = 110 different combinations.
This means that there are 110 different ways in which 2 students from different clubs can be selected.
If you want to learn more about combination and selections, you can read:
brainly.com/question/251701
I think you're missing a bit of the question. If her savings can be modeled by x...?
Answer:
Find in Step by Step
Step-by-step explanation:
x-intercept = 26/-4 = 13/-2 = -6.50000
y-intercept = 26/1 = 26.00000
Slope = 8.000/2.000 = 4.000
Equation at the end of step 1 :
(y - 6) - 4 • (x + 5) = 0
Step 2 :
Equation at the end of step 2 :
y - 4x - 26 = 0
Step 3 :
Equation of a Straight Line
3.1 Solve y-4x-26 = 0
Answer:
331.25
Step-by-step explanation:
First you want to find how much each class cost. So first you want to divide $198.75 by 15 and you will get 13.25. Once you do that you will multiply 13.25 by 25 to get 331.25. Your welcome.
