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3 years ago

Help again sorry imma just keep asking multible times. sorry i know i spelt wrong im in a rush

Mathematics

1 answer:

Sati [7]3 years ago

3 0

Answer:

is less than one, smaller

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List the ordered pairs shown in the mapping diagram

Ket [755]

Answer:

(0,4)

(1,6)

(2,8)

(3,1)

(4,0)

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2 years ago

What is the value of 15 when n=7

pashok25 [27]

Umm just do the problem with 7 in the place of N

4 0

3 years ago

Read 2 more answers

PLEASE HURRY!! simplify completely show all work for full credit

Irina18 [472]

Answer:

$4x^{3}$

Step-by-step explanation:

Given:

$(\frac{192x^{12}}{3x^{3}} )^{\frac{1}{3}}$

Apply exponent rule of distribution:

$\frac{(192x^{12})^{\frac{1}{3}}}{(3x^{3})^{\frac{1}{3}}}$

Simplify the numerator:

$\\\\\frac{4 * 3^{\frac{1}{3}}x^{4}}{(3x^{3})^{\frac{1}{3}}}$

Simplify the denominator:

$\\\frac{4 * 3^{\frac{1}{3}}x^{4}}{3^\frac{1}{3}x}}$

Simplify:

$4x^{3}$

-> To explain this party since it is a bigger jump, $3^{\frac{1}{3}}x$ is on the top and the bottom, so it becomes a one. We are left with a four on the top, and using properties of exponents 4 - 1 = 3, explaining why we have $x^{3}$ leftover too.

Have a nice day!

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

3 0

2 years ago

Which of the following equations is used to calculate the probability of event A happening, given that event B has occurred?

Naddika [18.5K]

Answer:

Step-by-step explanation:

Not much to explain

6 0

3 years ago

More on Areas. Farmer Jones, and his wife, Dr. Jones, both mathematicians, decide to build a fence in their field to keep the sh

Olin [163]

Answer:

Area covered by the fences will be 16.1 unit²

Step-by-step explanation:

Let the first parabola is represented by the function f(x) = 6x²

and second parabola by g(x) = x² + 9

point of intersection of the graphs will be determined when f(x) = g(x)

6x² = x² + 9

5x² = 9

x² = 1.8

x = ± 1.34

Now we will find the area between these curves drawn on the graph.

Area = $\int_{-1.34}^{1.34}[f(x)-g(x)]dx=\int_{-1.34}^{1.34}[6x^{2}-(x^{2}+9)]dx$

= $\int_{-1.34}^{1.34}(5x^{2}-9)dx$

= $[\frac{5}{3}x^{3}-9x]_{-1.34}^{1.34}$

= $[\frac{5}{3}(-1.34)^{3}-9(-1.34)-\frac{5}{3}(1.34)^{3}+9(1.34)]$

= $[-4.01+12.06-4.01+12.06]$

= 16.1 unit²

6 0

3 years ago