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lisabon 2012 [21]
3 years ago
15

Help again sorry imma just keep asking multible times. sorry i know i spelt wrong im in a rush

Mathematics
1 answer:
Sati [7]3 years ago
3 0

Answer:

is less than one, smaller

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I need help with this problem. This confuses me quite a lot and I’m having trouble and I would very much appreciated if someone
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a.

Step-by-step explanation:

because > means at most < means at least

8 0
3 years ago
Jessa had 23 one dollar bills that she wants to divide equally between her 5 children. How much money will each receive? How muc
vazorg [7]

Answer:

$4.06

Step-by-step explanation:

23 / 5 = 4

Remainder = 3

$3 into dimes = 30 dimes

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2 years ago
Find the y-intercept for the parabola defined by the equation y=x^2-x-12
o-na [289]

Answer:

The y-intercept is (0,-12).

Step-by-step explanation:

Given equation is y=x^2-x-12.

Now question says to find the y-intercept of the given parabola y=x^2-x-12.

We know that y-intercept means the y-value when x-value equals 0

so let's plug x=0 into given equation y=x^2-x-12  then solve that for y.

y=x^2-x-12

y=0^2-0-12

y=0-0-12

y=-12

Hence the y-intercept is (0,-12).

6 0
3 years ago
For the following integral, give a power or simple exponential function that if integrated on a similar infinite domain will hav
zhannawk [14.2K]

Answer:

hello your question is incomplete attached below is the complete question

answer :

for  I1 =     \frac{1}{x^2} + \frac{4}{x^3}    The integral converges

for  I2 =    \frac{2x + 6}{2(x^2 + 6x + 4 )}  The integral diverges

for  I3 =  \frac{1}{x^2}  The integral converges

for  I4 = 1  The integral diverges

Step-by-step explanation:

The similar integrands and the prediction ( conclusion )

for  I1 =     \frac{1}{x^2} + \frac{4}{x^3}    The integral converges

for  I2 =    \frac{2x + 6}{2(x^2 + 6x + 4 )}  The integral diverges

for  I3 =  \frac{1}{x^2}  The integral converges

for  I4 = 1  The integral diverges

attached below is a detailed solution

5 0
3 years ago
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