1.)
-x=3-4x+6
3x=3+6
3x=9
X=3
c
2.)
-6+x=-2
x=4
B
First you collect the like term then variable one side coefficient one side and constant
The y intercept is 0, and the slope is 5x.
Equation: y = 5x +0.
Answer:
Probability of having at least 4 Girls
= 0.6875
Step-by-step explanation:
Probability of having at least 4 Girls is 1-probability of having exactly 3 girls
Total number of children= 5 = N
Probability of having a girl p = 0.5
Probability of not having a girl q= 0.5
X= 3
Probability of at least 4 girls is given by
Probability= NCX(p)^x(q)^(N-x)
Probability = 5C3(0.5)^3(0.5)^(5-3)
Probability = 5C3(0.5)^3(0.5)^2
Probability= 5!/3!2!(0.5)^3(0.5)^2
Probability= 10(0.125)(0.25)
Probability= 0.3125
Probability of having at least 4 Girls
= 1- 0.3125
= 0.6875
Answer:
21
Step-by-step explanation:
PEMDAS:
Parenthesis
Exponent
Multiplication and Division
Addition and Subtraction
21-3+3
18+3
21
Hope this helps!
