3 years ago

Use the graph to write the factorization of x2 - x-6. 10- y = x2 - X - 6

Mathematics

1 answer:

Zolol [24]3 years ago

6 0

Answer:

x^2 -x -6

x^2 -x(3-2)-6

x^2 -3x +2x -6

x(x-3) +2(x-3)

(x-3) (x+2)

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oksian1 [2.3K]

Lol i forgot how to do this. Sorrryyy.

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2 years ago

On a test with 25 questions grace got 88% correct how many problems did grace get correct

mariarad [96]

88/100 can be simplified. Divide both sides by 4 which turns it into 22/25.
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3 years ago

If (a−8)/3=(a−3)/2 , then a = ?

Tresset [83]

Answer:

$\frac{(a - 8)}{3} = \frac{(a - 3)}{2} \\ 2(a - 8) = 3(a - 3) \\ 2a - 16 = 3a - 9 \\ 3a - 2a = - 7 \\ a = - 7$

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2 years ago

Read 2 more answers

If a family has 6 children, in how many ways could the parents have 3 boys and 3 girls?

Jlenok [28]

The parents could have 3 boys and 3 girls in 400 ways

<h3>How to determine the number of ways?</h3>

The given parameters are

Children, n = 6

Boys, r = 3

Girls, r =3

The number of combination is:

$Ways = ^nC_{r1} *^nC_{r2}$

So, we have:

$Ways = ^6C_3 *^6C_3$

Apply the combination formula

$Ways = \frac{6!}{3!3!} *\frac{6!}{3!3!}$

This gives

Ways = 400

Hence, the parents could have 3 boys and 3 girls in 400 ways

Read more about combination at:

brainly.com/question/11732255

#SPJ1

4 0

1 year ago

Factor completely x2 + 16.<br><br> (x + 4)(x + 4)<br> (x + 4)(x − 4)<br> Prime<br> (x − 4)(x − 4)

Sindrei [870]

It's prime because the constant term is positive and there is no middle term. If it were x^2 - 16, we could use (x+4)(x-4), but because 16 is positive, it cannot be factored

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3 years ago