Answer: The 95% confidence interval for the mean of x is (94.08, 101.92) .
Step-by-step explanation:
We are given that ,
A random variable x has a Normal distribution with an unknown mean and a standard deviation of 12.
i.e.
Also, it is given that , Sample mean having sample size : n= 36
For 95% confidence ,
Significance level :
By using the z-value table , the two-tailed critical value for 95% Confidence interval :
We know that the confidence interval for unknown population mean is given by :-
, where = Sample mean
= Population standard deviation
= Critical z-value.
Substitute all the given values, then the required confidence interval will be :
Therefore, the 95% confidence interval for the mean of x is (94.08, 101.92) .
4y⁴ - 8y³ - (5y³ + 6y + 3y⁴)
= 4y⁴ - 8y³ - 5y³ - 6y - 3y⁴
= (4y⁴ - 3y⁴) + (- 8y³ - 5y³) - 6y
= y⁴ - 13y³ - 6y
Answer: y⁴ - 13y³ - 6y
Answer: X= -9
Explanation:
Expand.
3(x+15)−6x=−6(x−3)
Simplify 3x+45-6x to -3x+45.
-3x+45−6x=−6x+18
Add 6x to both sides.
−3x+45=−6x+18
Simplify-3x+45+6x to 3x+45.
3x+45=18
Subtract 45 from both sides.
3x=18−45
Simplify 18-45 to -27.
3x=−27
Divide both sides by 3
X=-27/3
Simplify 27/3 to 9.
(X=-9)