Answer:
the answer would be C. The mean would increase.
Step-by-step explanation:
So, its 18.5 per person
<span><span>
80/5=16
18.5-16=2.5
They would each save 2.5 dollars each.</span></span>
Answer:
The solution to the system of equations is y = -5 and x = -2.
Step-by-step explanation:
The question tells us to use substitution to solve the system. This means that the given value for x (in terms of y) should be substituted into the other equation. This is modeled below:
-4y - 5x = 30
-4y - 5(y+3) = 30
Next, we should use the distributive property to simplify the left side of the equation.
-4y -5y - 15 = 30
The next step is to combine like terms on the left side of the equation.
-9y - 15 = 30
Then, we can add 15 to both sides of the equation.
-9y = 45
Finally, we can divide both sides of the equation by -9.
y = -5
To find the value for x, we substitute in the value we just found for y into either of our original equations.
x = y + 3
x = -5 + 3
x = -2
Therefore, the correct answer is y = -5 and x = -2.
Hope this helps!
Answer:
its b
Step-by-step explanation:
it's b yup yup yeah yeah
Answer:
40.1% probability that he will miss at least one of them
Step-by-step explanation:
For each target, there are only two possible outcomes. Either he hits it, or he does not. The probability of hitting a target is independent of other targets. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which 
is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
0.95 probaiblity of hitting a target
This means that 
10 targets
This means that 
What is the probability that he will miss at least one of them?
Either he hits all the targets, or he misses at least one of them. The sum of the probabilities of these events is decimal 1. So
We want P(X < 10). So
In which
40.1% probability that he will miss at least one of them
