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oksano4ka [1.4K]
3 years ago
9

WORTH 99 POINTS IF YOU ANSWER ALL!

Mathematics
2 answers:
Daniel [21]3 years ago
8 0
1) C. <u>19.4
</u>1/3(3)^3 + 5.2(2)
1/3(27) + 10.4
9 + 10.4
= 19.4

2) C. <u>6
</u>9 - (1/2)^4 * 48
9 - 0.0625 * 48
9 - 3
= 6

3) A. <u>2 times y divided by 7</u>
4) C. <u>5p - 4</u>
5) C. <u>Step 2; 4(2) + 4(4x)

</u>Hope this helps!<u>
</u>
malfutka [58]3 years ago
7 0
What is the value of fraction 1 over 3x3 + 5.2y when x = 3 and y = 2?

C. 19.4

just substitude the value into the equation given

Question 6(Multiple Choice Worth 1 points)
(06.01 MC)

What is the value of the expression 9 − (fraction 1 over 2)4 ⋅ 48?

D. 9

the answer is 8.9375,but the answer provided in whole number.You just need to round off to tge nearest whole number.

Question 7(Multiple Choice Worth 1 points)
(06.02 LC)

Which statement best describes the expression 2y ÷ 7?

A. 2 times y divided by 7

B,C and D are obviously wrong.It doesn't related on the equation given.A is the right answer

Question 8(Multiple Choice Worth 1 points)
(06.02 MC)

Which of these is the algebraic expression for "4 less than the product of 5 and some number?"

B. 4 − 5p

A,C and D are WRONG. it doesn't mention that 4 is the product of any unknown number.B is the right answer

Question 9(Multiple Choice Worth 1 points)
(06.06 MC)

The work of a student to find the dimensions of a rectangle of area 8 + 16x and width 4 is shown below:

A. Step 1: 8 + 16x
B. Step 2: 4(4) + 4(12x)
C. Step 3: 4(4 + 12x)
D. Step 4: Dimensions of the rectangle are 4 and 4 + 12x

In which step did the student first make an error and what is the correct step?

C. Step 2; 4(2) + 4(4x)

The first error is at the step 2.It doesn't show the right solution.4(4x),not 4(12x).That is obviously wrong.How could 16 can be 12 even the expression not multiply by any number yet ! that obviously WRONG. C is the right answer




You might be interested in
Statistics professors believe the average number of headaches per semester for all students is more than 18. From a random sampl
kompoz [17]

Complete Question

Statistics professors believe the average number of headaches per semester for all students is more than 18. From a random sample of 15 students, the professors find the mean number of headaches is 19 and the standard deviation is 1.7. Assume the population distribution of number of headaches is normal.the correct conclusion at \alpha =0.001 is?

Answer:

There is no sufficient evidence to support the professor believe

Step-by-step explanation:

From the question we are told that

     The population mean is  \mu =  18

     The sample size is  n  =  15

      The sample mean is  \=  x  =  19

      The standard deviation is  \sigma =  1.7

      The level of significance is  \alpha  =  0.001

The null hypothesis is  H_o:  \mu = 18

The  alternative hypothesis is  H_a :  \mu > 18

 The critical value of the level of significance from the normal distribution table is    

         Z_{\alpha } =  3.290527

The test hypothesis is mathematically represented as

           t =  \frac{\= x  -  \mu }{ \frac{\sigma}{ \sqrt{n} } }

substituting values  

         t =  \frac{ 19  - 18}{ \frac{1.7}{ \sqrt{15} } }

         t =  2.28

Looking at the value of  t and  Z_{\alpha } we can see that t <  Z_{\alpha } so we fail to reject the null hypothesis.

This mean that there is no sufficient evidence to support the professor believe

     

       

3 0
3 years ago
50 points + brainlest if you answer correctly
Mumz [18]

Answer:

  • <u>5</u><u> </u>is the value which makes the equation true .

Step-by-step explanation:

In this question we have provided an equation that is <u>9</u><u> </u><u>(</u><u> </u><u>3x</u><u> </u><u>-</u><u> </u><u>1</u><u>6</u><u> </u><u>)</u><u> </u><u>+</u><u> </u><u>1</u><u>5</u><u> </u><u>=</u><u> </u><u>6</u><u>x</u><u> </u><u>-</u><u> </u><u>2</u><u>4</u><u> </u>. And we are asked to <u>write </u><u>the </u><u>steps </u><u>to </u><u>solve </u><u>the </u><u>equation </u><u>with </u><u>explanation </u> and <u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>X </u><u>.</u>

<u>Solution</u><u> </u><u>:</u><u> </u><u>-</u>

\longmapsto \quad \: 9(3x - 16) + 15 = 6x - 24

<u>Step </u><u>1</u><u> </u><u>:</u> Solving parenthesis on left side using distributive property which means multiplying 9 with 3x as well as -16 :

\longmapsto \quad \:27x -  \bold{144 }+  \bold{15 }= 6x - 24

<u>Step </u><u>2</u><u> </u><u>:</u> Solving like terms on left side that are -144 and 15 :

\longmapsto \quad \:27x -129 = 6x - 24

<u>Step </u><u>3 </u><u>:</u> Adding 129 on both sides :

\longmapsto \quad \:27x - \cancel{129} -  \cancel{129} = 6x \bold{ - 24 } +  \bold{129}

Now on cancelling -129 with 129 on left side and solving the terms that are -24 and 129 on right side , We get :

\longmapsto \quad \:27x = 6x + 105

<u>Step </u><u>4</u><u> </u><u>:</u> Subtracting with 6x on both sides :

\longmapsto \quad \: \bold{27x} -  \bold{6x} =  \cancel{6x} +105 - \cancel{ 6x}

On calculating further, We get :

\longmapsto \quad \:21x =  105

<u>Step </u><u>5</u><u> </u><u>:</u> Now we are Dividing with 21 on both sides so that we can isolate the variable that is x :

\longmapsto \quad \: \dfrac{ \cancel{21}x}{ \cancel{21}}  = \dfrac{105}{ 21}

Now , by cancelling 21 with 21 on left side , We get :

\longmapsto \quad \:x =  \cancel{\dfrac{105}{21}}

<u>Step </u><u>6</u><u> </u><u>:</u> Now our final step is to simplify the value of x that is 105/21 . We know that 21 × 5 is equal to 105 . So :

\longmapsto \quad \:    \purple{\underline{\boxed{\frak{ x =  5 }}}}

  • <u>Henceforth</u><u> </u><u>,</u><u> </u><u>value </u><u>of </u><u>x </u><u>is </u><u>5</u>

<u>Verifying</u><u> </u><u>:</u><u> </u><u>-</u>

Now we are verifying our answer by substituting value of x in the given equation . So ,

  • 9 ( 3x - 16 ) + 15 = 6x - 24

  • 9 [ 3 ( 5 ) - 16 ] + 15 = 6 ( 5 ) - 24

  • 9 ( 15 - 16 ) + 15 = 30 - 24

  • 9 ( -1 ) + 15 = 6

  • -9 + 15 = 6

  • 6 = 6

  • L.H.S = R.H.S

  • Hence , Verified .

<u>Therefore</u><u>,</u><u> our</u><u> value</u><u> for</u><u> x</u><u> is</u><u> correct</u><u> </u><u>that </u><u>means</u><u> </u><u>it'll</u><u> </u><u>makes</u><u> </u><u>the </u><u>equation</u><u> true</u><u> </u><u>.</u>

<h2><u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>
4 0
2 years ago
A simple random sample of 32 men from a normally distributed population results in a standard deviation of 12.9 beats per minute
krok68 [10]

Answer:

Null Hypothesis, H0 = The pulse rates of men have a standard deviation equal to 10 beats per minute

Alternate Hypothesis, H1 = The pulse rates of men do not have a standard deviation equal to 10 beats per minute

Step-by-step explanation:

The null hypothesis is basically the problem statement i.e

Pulse rates of men have a standard deviation equal to 10 beats per minute

Hence, H0 = The pulse rates of men have a standard deviation equal to 10 beats per minute

The alternate hypothesis will contradict or negate the null hypothesis i.e

H1 = The pulse rates of men do not have a standard deviation equal to 10 beats per minute

4 0
2 years ago
I need help please...............
Arte-miy333 [17]

Answer:

I cant see the entire question

Step-by-step explanation:

4 0
3 years ago
Answer this question plz
olya-2409 [2.1K]

Answer: velocity-time graph

Step-by-step explanation: The principle is that the slope of the line on a velocity-time graph reveals useful information about the acceleration of the object. If the acceleration is zero, then the slope is zero (i.e., a horizontal line). If the acceleration is positive, then the slope is positive (i.e., an upward sloping line).

8 0
3 years ago
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