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Dahasolnce [82]
3 years ago
6

Solve - 4x2 - 4x - 9 = 0, stating your solutions in the form a = bi. Someone please answer!!

Mathematics
1 answer:
PIT_PIT [208]3 years ago
6 0

Answer:

x=-0.5 \pm -i\sqrt{2}

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS

<u>Algebra I</u>

  • Standard Form: ax² + bx + c = 0
  • Quadratic Formula: x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}

<u>Algebra II</u>

  • Imaginary Roots: √-1 = i
  • Standard Form: a + bi

Step-by-step explanation:

<u>Step 1: Define</u>

-4x² - 4x - 9 = 0

a = -4

b = -4

c = -9

<u>Step 2: Find roots</u>

  1. Substitute:                    x=\frac{4\pm\sqrt{(-4)^2-4(-4)(-9)} }{2(-4)}
  2. Exponents:                   x=\frac{4\pm\sqrt{16-4(-4)(-9)} }{2(-4)}
  3. Multiply:                        x=\frac{4\pm\sqrt{16-144} }{-8}
  4. Subtract:                       x=\frac{4\pm\sqrt{-128} }{-8}
  5. Factor:                          x=\frac{4\pm \sqrt{-1} \cdot \sqrt{128} }{-8}
  6. Simplify:                       x=\frac{4\pm 8i\sqrt{2} }{-8}
  7. Factor:                          x=\frac{4(1\pm 2i\sqrt{2}) }{-8}
  8. Divide:                          x=\frac{1\pm 2i\sqrt{2}}{-2}
  9. Expand:                        x=\frac{-1}{2} \pm \frac{-2i\sqrt{2} }{2}
  10. Simplify:                        x=\frac{-1}{2} \pm -i\sqrt{2}
  11. Evaluate:                      x=-0.5 \pm -i\sqrt{2}
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