(2x-15) + 11x = 180
Combine your like terms in get
13x - 15 = 180
Add 15 on both sides
13x - 15 = 180
+15 + 15
13x = 195
Divide each side by 13 and get
x = 15
-4 is the answer in this problem
Answer: No, they would not get the same amount.
Step-by-step explanation:
Let the number of coins be x
Eliot counts a group of coins staring with the quarters.
As we know that

So, Number of amount Eliot counts with the quarters is given by

Similarly, His sister counts the same coins she counting the pennies .
As we know that

So, Total amount his sister counts with the pennies is given by

But we can see that

Hence, No, they would not get the same amount.
Answer:
cos(θ) = 3/5
Step-by-step explanation:
We can think of this situation as a triangle rectangle (you can see it in the image below).
Here, we have a triangle rectangle with an angle θ, such that the adjacent cathetus to θ is 3 units long, and the cathetus opposite to θ is 4 units long.
Here we want to find cos(θ).
You should remember:
cos(θ) = (adjacent cathetus)/(hypotenuse)
We already know that the adjacent cathetus is equal to 3.
And for the hypotenuse, we can use the Pythagorean's theorem, which says that the sum of the squares of the cathetus is equal to the square of the hypotenuse, this is:
3^2 + 4^2 = H^2
We can solve this for H, to get:
H = √( 3^2 + 4^2) = √(9 + 16) = √25 = 5
The hypotenuse is 5 units long.
Then we have:
cos(θ) = (adjacent cathetus)/(hypotenuse)
cos(θ) = 3/5
Here, you have to determine values of f(x) for negative domain. Domain are those values of x for which function is defined.
Since the function is a polynomial, every value of x∈R is defined for f(x).
And for every negative value of x, f(x) will always be positive because x is squared and square of negative real number is always positive.
0 is neither negative nor positive. Therefore, zero is not included in negative domain. If you plug say x= -0.00000956, f(x) will be greater than 1 because square of x will never be negative.
Thus, the range will always be positive or greater than equal to 1.
Therefore, y≥1